如何在Google Maps JS API中获取仍包含一组Lat / Long坐标的最小LatLngBounds?

时间:2010-07-30 15:56:40

标签: javascript google-maps google-maps-api-3

我需要在地图上绘制一组坐标以响应用户选择,当它发生时,我想平移地图以专注于那组点。如何找到包含所有坐标的最小边界框(LatLngBounds)?

1 个答案:

答案 0 :(得分:12)

除了Stack Overflow post which @Crescent Fresh pointed to above(使用v2 API)之外,您要使用的方法是LatLngBounds.extend()

以下是使用v3 API

的完整示例
<!DOCTYPE html>
<html> 
<head> 
   <meta http-equiv="content-type" content="text/html; charset=UTF-8"/> 
   <title>Google Maps LatLngBounds.extend() Demo</title> 
   <script src="http://maps.google.com/maps/api/js?sensor=false" 
           type="text/javascript"></script> 
</head> 
<body> 
   <div id="map" style="width: 400px; height: 300px;"></div> 

   <script type="text/javascript"> 

   var map = new google.maps.Map(document.getElementById('map'), { 
     mapTypeId: google.maps.MapTypeId.TERRAIN
   });

   var markerBounds = new google.maps.LatLngBounds();

   var randomPoint, i;

   for (i = 0; i < 10; i++) {
     // Generate 10 random points within North East America
     randomPoint = new google.maps.LatLng( 39.00 + (Math.random() - 0.5) * 20, 
                                          -77.00 + (Math.random() - 0.5) * 20);

     // Draw a marker for each random point
     new google.maps.Marker({
       position: randomPoint, 
       map: map
     });

     // Extend markerBounds with each random point.
     markerBounds.extend(randomPoint);
   }

   // At the end markerBounds will be the smallest bounding box to contain
   // our 10 random points

   // Finally we can call the Map.fitBounds() method to set the map to fit
   // our markerBounds
   map.fitBounds(markerBounds);

   </script> 
</body> 
</html>

截图:

Google Maps LatLngBounds.extend() Demo