Question

示例：

Mysql - table_data

  dataid   dataname    datastatus
    1        joel          1
    1        joelle        2
    1        joe           3
    1        joela         4
    1        joella        5

PHP

 $names = array('joel','joelle','joe','joela');
 foreach($names as $name)
 {
    $qcheck = $this->db->query("SELECT * FROM table_data WHERE dataname=".$name."");
     //Do checking here
 }

我怎么知道joel，joelle，joe和joela datastatus是否都相同且不相同？

我如何知道该示例的输出..输出应该为false，因为所有状态都不相同，如果所有状态都相同，我怎么知道？

希望有人能提前帮助我...

Answer 1

尝试这种优化逻辑：

$namesStr = implode(',', $names);
$qcheck = $this->db->query("SELECT COUNT(DISTINCT datastatus) AS dataCount FROM table_data WHERE dataname IN($namesStr)");
$allSame = FALSE;
if ($qcheck->num_rows() >  0) {
    if ($qcheck->row()->dataCount == 1) {
        $allSame = TRUE;
    }
}

Answer 2

修改您的查询，如下所示。

$namesStr = "'" . implode("','", $names) . "'";
$qcheck = $this->db->query("SELECT COUNT(DISTINCT datastatus) AS dataCount FROM table_data WHERE dataname IN ($namesStr)");

您的查询看起来像......

SELECT COUNT(DISTINCT datastatus) AS dataCount FROM table_data WHERE dataname IN ('joel','joelle','joe','joela')

Answer 3

你可以这样试试，

$names = array('joel','joelle','joe','joela');
$qcheck = $this->db->query("SELECT datastatus FROM table_data WHERE dataname=".$name."")->result_array;
foreach($names as $name)
{
    if(in_array($name,$qcheck)){
        //name exists
    } else {
        //name doesnot exists
    }
}

Answer 4

试试这个逻辑

不需要implode array。只需在where_in中传递数组，就像这样 -

        $names = array('joel','joelle','joe','joela');
        $this->db->select("COUNT(DISTINCT datastatus) AS dataCount");
        $this->db->from("table_data");
        $this->db->where_in('dataname',$names);
        $q=$this->db->get();

        if($q->num_rows() >  0){
            $result=$q->row();

            if ($result->dataCount == 1) {
                echo "true";
            }
        }

PHP，MYSQL，FOREACH检查是否有相同的值

4 个答案: