Question

我想使用提交按钮在数据库中插入多行，这是我的观看代码

    @Entity
@Table(name = "tbl_user")
public class UserTO implements Serializable {

    private static final long serialVersionUID = -4082995725312571363L;

    @Id
    @GeneratedValue(generator = "system-uuid")
    @GenericGenerator(name = "system-uuid", strategy = "uuid")
    @Column(name = "USER_ID")
    private String userId;

    @Column(name = "USER_EMAIL")
    private String userEmail;

    @Column(name = "USER_PASSWORD")
    private String userPassword;

    @Column(name = "USER_NAME")
    private String userName;

    @Column(name = "USER_GENDER")
    private String userGender;

    @Column(name = "USER_DOB")
    private Date userDOB;

    @Column(name = "USER_CONTACT")
    private String userContact;

    @Column(name = "USER_ADDRESS")
    private String userAddress;

    public String getUserId() {
        return userId;
    }

    public void setUserId(String userId) {
        this.userId = userId;
    }

    public String getUserEmail() {
        return userEmail;
    }

    public void setUserEmail(String userEmail) {
        this.userEmail = userEmail;
    }

    public String getUserPassword() {
        return userPassword;
    }

    public void setUserPassword(String userPassword) {
        this.userPassword = userPassword;
    }

    public String getUserName() {
        return userName;
    }

    public void setUserName(String userName) {
        this.userName = userName;
    }

    public String getUserGender() {
        return userGender;
    }

    public void setUserGender(String userGender) {
        this.userGender = userGender;
    }

    public Date getUserDOB() {
        return userDOB;
    }

    public void setUserDOB(Date userDOB) {
        this.userDOB = userDOB;
    }

    public String getUserContact() {
        return userContact;
    }

    public void setUserContact(String userContact) {
        this.userContact = userContact;
    }

    public String getUserAddress() {
        return userAddress;
    }

    public void setUserAddress(String userAddress) {
        this.userAddress = userAddress;
    }

}

这是我的控制器代码

    <?php   
        foreach($role_array as $k =>$v)
        {
            //var_dump($k);
            if($k != "bookin_operator" && $k!= "production_manager" && $k != "client" && $k != "admin" )
            {

        ?>
            <div class="row-fluid"> 
                <div class="span6">      
                    <div class='control-group'>


                        <label for='<?php echo $k;  ?>' class='control-label'><?php  echo $v ;?></label>
                        <div class='controls'>
                            <select class='form-control' name='<?php echo $k;  ?>[]' id='<?php echo $k;  ?>' multiple='multiple' size='5'>
                                <?php

                                   foreach($all_datas[$k] as $datas ) 
                                   {

                                        $username = "{$datas->nickname}";

                                        echo "<option value='{$datas->id}'>{$username}</option>";
                                   }
                                ?>
                            </select>
                            <label for="<?php echo $k;  ?>" class="error" style="display:none"></label>
                        </div>
                    </div>                         
                </div>    

            </div>  
            <?php }} ?>

$ data output

            $roles = $this->utility->roles;
            foreach($roles as $k => $v)
            {
                if($k != "bookin_operator" && $k!= "production_manager" && $k != "client" && $k != "admin" && isset($post_data[$k]))
                {
                    $userrole = $k;
                    $post_user=isset($post_data[$k])?$post_data[$k]:'';

                    if (count($post_user) > 0)
                    {
                        for ($i = 0; $i < count($post_user); $i++)
                        {
                            $data = array("journal_id" => $new_journal_id,"user_role" => $userrole,"user_id" =>$post_user[$i]);
                           // var_dump($data);
                            $flag = true;



                        }
                    }
                }
            }

            if(isset($flag))
            {

                $v=$this->JournalUsers->addJournalUser($data);
            }

但是，当插入数据时，只会在表上插入一行。

    array(3) {
    ["journal_id"]=>int(83)
    ["user_role"]=>
    string(15) "quality_checker"
    ["user_id"]=>
    string(3) "136"
    }
    array(3) {
    ["journal_id"]=>
    int(83)
    ["user_role"]=>
    string(5) "texer"
    ["user_id"]=>
    string(3) "103"
    }
    array(3) {
    ["journal_id"]=>
    int(83)
    ["user_role"]=>
    string(5) "texer"
    ["user_id"]=>
    string(3) "133"
    }
     array(3) {
    ["journal_id"]=>
    int(83)
    ["user_role"]=>
    string(5) "texer"
    ["user_id"]=>
    string(3) "132"
    }
    array(3) {
   ["journal_id"]=>
   int(83)
   ["user_role"]=>
   string(10) "typesetter"
   ["user_id"]=>
   string(3) "109"
   }

   array(3) {
   ["journal_id"]=>
   int(83)
   ["user_role"]=>
   string(10) "typesetter"
   ["user_id"]=>
   string(3) "153"
   }

我想在db

中插入所有数据

Answer 1

这里$ data每次都重新初始化。像这样更新代码：

$data = array();
    $roles = $this->utility->roles;
        foreach($roles as $k => $v)
        {
            if($k != "bookin_operator" && $k!= "production_manager" && $k != "client" && $k != "admin" && isset($post_data[$k]))
            {
                $userrole = $k;
                $post_user=isset($post_data[$k])?$post_data[$k]:'';

                if (count($post_user) > 0)
                {
                    for ($i = 0; $i < count($post_user); $i++)
                    {
                        $data[] = array("journal_id" => $new_journal_id,"user_role" => $userrole,"user_id" =>$post_user[$i]);
                       // var_dump($data);
                        $flag = true;



                    }
                }
            }
        }

        if(isset($flag) && !empty($data))
        {

            $v=$this->JournalUsers->addJournalUser($data);
        }

在模型循环中如下：

public function addJournalUser($data) {
    foreach ($data AS $row) {
      // execute your insertion query with variable row   
    }
}

Answer 2

你也可以在模型中使用insert_batch，不需要foreach

$data = array(
   array(
      'title' => 'My title' ,
      'name' => 'My Name' ,
      'date' => 'My date'
   ),
   array(
      'title' => 'Another title' ,
      'name' => 'Another Name' ,
      'date' => 'Another date'
   )
);

$this->db->insert_batch('mytable', $data);

如何使用codeigniter在mysql中插入多行

2 个答案: