如何找到numpy数组的不同组合？

Question

我有以下numpy数组

[[0 6 0 0]
[0 7 0 0]
[0 1 0 0]
[0 7 0 0]
[3 4 6 0]
[2 1 4 0]
[3 1 2 0]
[3 1 2 0]
[0 1 2 0]
[1 7 1 3]
[0 3 6 7]]

我希望获得如下组合：

  1.[0 0 0 0 0 3 2 3 3 0 1 0]
  2.[6 6 7 1 7 4 1 1 1 1 7 3]
  3.[0 0 0 0 0 6 4 2 2 2 1 6]
  4.[0 0 0 0 0 0 0 0 0 0 3 7]
  5.[[0 6]
  [0 7]
  [0 1]
  [0 7]
  [3 4]
  [2 1]
  [3 1]
  [3 1]
  [0 1]
  [1 7]
  [0 3]]

依旧......

我们怎么能在循环中做到这一点？

Answer 1

n

这会为n的所有（合理）值获取长度为- (void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender { // Make sure your segue name in storyboard is the same as this line if ([[segue identifier] isEqualToString:@"YOUR_SEGUE_NAME_HERE"]) { // Get reference to the destination view controller YourViewController *vc = [segue destinationViewController]; // Pass any objects to the view controller here, like... vc.dictionary = self.dictionary. } } 的列的所有组合。