我在递归函数中使用foreach
循环。但我无法弄清楚在哪里通过我的退货声明。我需要在某个时候返回我的临时数组,但我不知道该怎么做:
<?php
$patterns = function($array, $temp = array(), $i = 0, $id = 0, $parent = 0) use(&$patterns) {
$return = null;
if(array_key_exists($i, $array)) {
foreach($array[$i] as $set) {
if($parent == $set['id']) {
$data = array(
'id' => $set['id'],
'parent' => $set['parent']
);
array_push($temp, $data);
}
$patterns($array, $temp, $i + 1, $set['id'], $set['parent']);
}
}
};
print_r($patterns($rev_relations));
?>
这是我的数据:
Array(
[0] => Array(
[0] => Array(
[id] => 60
[parent] => 55
)
[1] => Array(
[id] => 57
[parent] => 54
)
)
[1] => Array(
[0] => Array(
[id] => 61
[parent] => 50
)
[1] => Array(
[id] => 54
[parent] => 49
)
)
[2] => Array(
[0] => Array(
[id] => 49
[parent] => 0
)
)
)
答案 0 :(得分:1)
<?php
//pass $temp by reference so outside variable gets populated
$patterns = function($array, &$temp, $i = 0, $id = 0, $parent = 0) use(&$patterns) {
$return = null;
if(array_key_exists($i, $array)) {
foreach($array[$i] as $set) {
if($parent == $set['id']) {
$data = array(
'id' => $set['id'],
'parent' => $set['parent']
);
array_push($temp, $data);
}
$patterns($array, $temp, $i + 1, $set['id'], $set['parent']);
}
}
};
//actuall array is created on temp here
$temp=array();
$patterns($rev_relations,$temp);
?>
这不行吗?从来没有真正使用无名函数,但这就是我将如何在一个正常的递归函数上进行它
好的,拿两个
<?php
$patterns = function($array, $temp = array(), $i = 0, $id = 0, $parent = 0) use(&$patterns) {
$return = null;
if(array_key_exists($i, $array)) {
foreach($array[$i] as $set) {
if($parent == $set['id']) {
$data = array(
'id' => $set['id'],
'parent' => $set['parent']
);
array_push($temp, $data);
}
return $patterns($array, $temp, $i + 1, $set['id'], $set['parent']);
}
}
else
{
return $temp;
}
};
$patterns($rev_relations);
?>