Question

public class Tile extends JLabel{

private char _c;
static char randomChar;

public Tile(char c, Color background) {
    super();
    setBackground(background);
    setOpaque(true);
    _c = c;

}

public static char randomLetter() {
    Random r = new Random();
    randomChar = (char) (97 + r.nextInt(25));
    return randomChar;
    }

public static char getChar(){
    return Tile.randomLetter();
}

public static String convert(){
    char ch = Tile.randomLetter();
    return String.valueOf(ch);


}

public static void main(String[] args) {
    Tile tile = new Tile(Tile.convert(), Color.BLUE);
    Tile tile1 = new Tile(Tile.randomLetter(), Color.RED);
    Tile tile2 = new Tile(Tile.randomLetter(), Color.GREEN);
    Tile tile3 = new Tile(Tile.randomLetter(), Color.YELLOW);

    JFrame frame = new JFrame();
    frame.getContentPane().setLayout(new GridLayout(4,1));
    frame.setSize(500, 800);
    frame.setVisible(true);
    frame.add(tile);
    frame.add(tile1);
    frame.add(tile2);
    frame.add(tile3);

    System.out.println(Tile.convert());

所以我试图制作一个游戏，有四个瓷砖，我使用Jlabels作为我的瓷砖。我的瓷砖有一个字符和一个颜色，因为jlabels不接受字符，我试图制作一个方法将我的字符转换为字符串，然后将它放在我的jlabel中，以便接受它。我该怎么做？

Answer 1

假设一个名为#include <stdio.h> #include <stdlib.h> #include <ctype.h> int main(void) { /* You need an array of int's with size equal to the number of letters * int the alphabet */ int count['Z' - 'A' + 1]; /* You need some space to store the text, `str' will become a poitner * when you pass it to `fgets()' pointing to an array of 1000 `chars' */ char str[1000]; /* Initialize all the counters to 0 */ for (int i = 0 ; i < sizeof(count) / sizeof(*count) ; ++i) count[i] = 0; printf("Enter any string : "); /* Read the string, use `fgets()` and prevent a buffer overflow */ if (fgets(str, sizeof(str), stdin) == NULL) return -1; /* Now count the letters */ for (int i = 0 ; ((str[i] != '\0') && (str[i] != '\n')) ; ++i) { /* If it's not a letter, go to the next one */ if (isalpha((int) str[i]) == 0) continue; /* It's a letter, count it at the correct position */ count[toupper((int) str[i]) - 'A'] += 1; } /* Print the count of each letter, skipping those that did not appear */ for (int i = 0 ; i < sizeof(count) / sizeof(*count) ; ++i) { if (count[i] == 0) continue; fprintf(stderr, "Number of %c's : %d\n", i + 'A', count[i]); } return 0; }的char变量，就像

一样简单

myChar

会起作用。

将char转换为字符串，然后将其插入JLabel

1 个答案: