Question

我正在尝试传递两个隐藏字段和一个答案来创建一个新的答案对象。尽管我可以看到散列中的所有参数，但似乎隐藏的参数没有正确包含在答案中。我确定这只是一件简单的事情，我做错了但却无法弄清楚它在哪里。欣赏时间！

Params Hash：

参数：

{"utf8"=>"✓",
 "authenticity_token"=>"VaZC2MCN0rWJnVPIqSTbPF9HvFNBfm5b5nA3H8YenuVte9SMi9Iy+G4fxz9bWhkDNwGVz9jMBVTxT/SuXFCh+A==",
 "user_id"=>"2",
 "question_id"=>"1",
 "answer"=>{"answer"=>"a"},
 "commit"=>"Create Answer"}

错误： SQLite3 :: ConstraintException：NOT NULL约束失败：answers.user_id：INSERT INTO“answers”（“created_at”，“updated_at”）VALUES（？，？）

_mc_answer.html.erb（部分我用作多项选择题的表单。）

这应该将question_id和user_id以及用户的回答传递到static_pages控制器并创建一个新的Answer对象。

<h4>MC Answer:</h4>
  <p>User ID: <%= @user.id %></p>
  <p>Question ID: <%= question_id %></p>
  <%= form_for(@new_answer, url: static_pages_path(@new_answer)) do |a| %>
    <%= hidden_field_tag :user_id, @user.id %>
    <%= hidden_field_tag :question_id, question_id %>
    <%= a.text_field :answer %>
    <%= a.submit %>
  <% end %>

static_pages_controller.rb

class StaticPagesController < ApplicationController

  def index
    @user = current_user

    if user_signed_in?  
      if @user.manager_id != nil
        @manager = @user.manager_id
      end
      @my_team = User.where("manager_id = ? AND id != ?", @manager, @user.id)
      @questions = Question.active_question.where.not(id: @user.answers)     
    end
    @new_answer = Answer.new
  end

  def new
    @new_answer = Answer.new
  end

  def create
    @user = current user ## Tried adding this to the create method per suggestion below but still getting the same issue. 
    @new_answer = Answer.new(answer_params)
    if @new_answer.save!
      flash.now[success]
    else
    end  
  end

  private


  ## Edited params from .permit(:answer => [:user_id, :question_id, :answer]) but still getting similar error.
  def answer_params
    params.require(:answer).permit(:user_id, :question_id, :answer)
  end
end

answer.rb模型

class Answer < ActiveRecord::Base


  belongs_to :question
  belongs_to :user

  scope :user_answered, lambda {|q| where("question_id == (?)", q) }


  def next
    Answer.where("id > ?", id).limit(1).first
  end

  def prev
    Answer.where("id < ?", id).limit(1).first
  end  
end



DB Schema for answer model if that's of any use: 

ActiveRecord::Schema.define(version: 20151112025039) do

  create_table "answers", force: :cascade do |t|
    t.integer  "user_id",       null: false
    t.integer  "question_id",   null: false
    t.integer  "points_earned"
    t.text     "comment"
    t.text     "answer",        null: false
    t.datetime "created_at",    null: false
    t.datetime "updated_at",    null: false
  end


  add_index "users", ["confirmation_token"], name: "index_users_on_confirmation_token", unique: true
  add_index "users", ["email"], name: "index_users_on_email", unique: true
  add_index "users", ["reset_password_token"], name: "index_users_on_reset_password_token", unique: true
  add_index "users", ["unlock_token"], name: "index_users_on_unlock_token", unique: true

end

Answer 1

您应该将每个Symbol传递给控制器而不是Hash数组。

  def answer_params
    params.require(:answer).permit(:answer, :user_id, :question_id)
  end

不

 def answer_params
    params.require(:answer).permit(:answer => [:user_id, :question_id, :answer])
  end

因为您的"user_id"=>"2",和"question_id"=>"1"不在子哈希中，就像它写成"answer"=>{"answer"=>"a", "question_id"=>"1","user_id"=>"2" },

一样

Answer 2

您的隐藏字段参数不会进入正确位置的参数哈希值，因为您使用了hidden_field_tag并且没有指定它们包含在answer下面哈希中的键。试试这个：

<%= hidden_field_tag "answer[user_id]", @user.id %>

Rails隐藏的参数未正确传递

2 个答案: