Question

我的表格中有这些数据，如果我的查询来自end_time和+----+---------------------+---------------------+ | id | start_time | end_time | +----+---------------------+---------------------+ | 3 | 2015-11-09 04:00:00 | 2015-11-09 20:00:00 | | 6 | 2015-11-09 04:00:00 | 2015-11-09 10:00:00 | | 7 | 2015-11-09 06:00:00 | 2015-11-09 17:00:00 | | 8 | 2015-11-09 15:00:00 | 2015-11-09 20:00:00 | | 9 | 2015-11-09 01:00:00 | 2015-11-09 05:00:00 | +----+---------------------+---------------------+ 06:00 17:00 | | | | 1. S------E | | | | | | 2. S------E | | | | | 3. | S------E | | | | | 4. S----------------------E | | | | 5. | S------E | | | | 6. | | S------E时间'06：00：00' - '17：00：00，我想计算小时和分钟'并计算不在'06：00：00'到'17：00：00'

之间的日期

注意：start_time（'06：00：00'）和end_time（'17：00：00'）不是静态的，只是在表格中输入。

这是我表格中的数据。

SELECT id,Time_to_sec(Timediff(Least(Time(end_time), '17:00:00'),
                          Least(Time(start_time), '06:00:00'))) / 3600 AS
       outside
FROM   activelogs
WHERE  (Time(start_time) < '06:00:00' OR Time(end_time) > '17:00:00')


     AND Date(start_time) >= '2015-11-01'
     AND Date(end_time) <= '2015-11-20'

这是我的尝试。

+----+---------+
| id | outside |
+----+---------+
|  3 |       5 |
|  6 |       2 |
|  8 |       3 |
|  9 |       4 |
+----+---------+

预期输出

ABug.symbol

Answer 1

如果我理解正确，您希望在特定边界之外花费的时间。让我们在几秒钟内完成计算。您可以将其转换为您喜欢的任何内容：

SELECT id,
       (greatest(time_to_sec(least(time(end_time), '06:00:00')) - time_to_sec(start_time), 0) +
        greatest(time_to_sec(end_time) - time_to_sec(greatest(time(start_time), '17:00:00')), 0)
       ) as outside_seconds
FROM activelogs
WHERE Date(start_time) >= '2015-11-01' AND Date(end_time) <= '2015-11-20';

此计算有两个组成部分。第一个是上午6点之前的时段，第二个是下午5点之后的时段。

要消除id = 7，您可以修改where子句：

WHERE Date(start_time) >= '2015-11-01' AND Date(end_time) <= '2015-11-20' AND
      (Time(start_time) < '06:00:00' OR Time(end_time) > '17:00:00')

Answer 2

这也是诀窍

SELECT 
    id,    
    CASE 
        WHEN (HOUR(start_time) < 6) AND (HOUR(end_time) > 17) THEN 
            (6 - HOUR(start_time) + HOUR(end_time) -17)
        WHEN (HOUR(start_time) between 6 AND 17) AND (HOUR(end_time) > 17) THEN 
            (HOUR(end_time) -17)
        WHEN (HOUR(start_time) < 6) AND (HOUR(end_time) between 6 AND 17) THEN 
            (6 - HOUR(start_time))
        WHEN (HOUR(start_time) > 17) AND (HOUR(end_time) > 17) THEN 
            (HOUR(end_time) - HOUR(start_time)) 
        WHEN (HOUR(start_time) < 6) AND (HOUR(end_time) < 6) THEN 
            (HOUR(end_time) - HOUR(start_time)) 
        ELSE 0
    END as outside
FROM activelogs

计算两个日期以获得小时和分钟

2 个答案: