Question

我在Play中创建了一个允许用户上传文件的最小网站。虽然所涉及的代码相当简单，但我无法找到编译错误的原因：

Cannot write an instance of views.html.uploadFile.type to HTTP response. Try to define a Writeable[views.html.uploadFile.type]

以下是views.uploadFile.scala.html的内容：

@helper.form(action = routes.FileUpload.handleUpload, 'enctype -> "multipart/form-data") {
  File to upload: <input type="file" name="uploadedFile">

  <div> <input type="submit"> </div>
}

控制器显示文件上传表单并处理上传的文件：

package controllers

import play.api.i18n.{MessagesApi, I18nSupport}
import play.api.mvc._
import javax.inject.Inject

class FileUpload @Inject()(val messagesApi: MessagesApi) extends Controller with I18nSupport {
  def uploadForm = Action {
    Ok(views.html.uploadFile)
  }

  def handleUpload = Action(parse.multipartFormData) { request =>
    import java.io.File
    request.body.file("uploadedFile") match {
      case Some(file) =>
        val fileName = file.filename
        val uploadDir = "/tmp/uploadedFiles/"
        file.ref.moveTo(new File(uploadDir + fileName))
        Ok(s"File uploaded: $fileName")

      case None =>
        Redirect(routes.FileUpload.uploadForm()).flashing(
          "error" -> "File invalid")
    }
  }
}

为了完整起见，请点击我的routes文件：

GET         /uploadForm          @controllers.FileUpload.uploadForm
POST        /upload              @controllers.FileUpload.handleUpload

Answer 1

我忽略了控制器动作中缺少的括号：

def uploadForm = Action {
  // instead of Ok(view.html.uploadFile)
  Ok(views.html.uploadFile()) 
}

添加它们可以使应用程序编译正常。

Scala Play文件上传：无法将views.html.uploadFile.type的实例写入HTTP响应

1 个答案: