Question

我有一个由thrift struct生成的thrift类：

struct Chapter {
    1: required i32 id,
    2: optional string name,
    3: optional string desc,
    4: optional i32 questionCount,
    5: optional i32 keypointId,
}

据我所知，我们可以使用TSimpleJSONProtocol.Factory序列化对象而不需要setXXX和null成员。但是，如何序列化Chapter对象列表。当我使用Jackson时，必须有一些setXXX，如下所示：

[{"name":"ch1","desc":null,"questionCount":0,"keypointId":1,"setName":true,"setDesc":false,"setQuestionCount":false,"setKeypointId":true},{"name":"ch2","desc":null,"questionCount":0,"keypointId":2,"setName":true,"setDesc":false,"setQuestionCount":false,"setKeypointId":true}]

但我需要的是：

[{"name":"ch1","keypointId":1},{"name":"ch2","keypointId":2}]

我的简单解决方案是加入每个对象：

public static <T extends TBase> String writeValuewithTBase(Collection<T> c) {
    try {
        if (c == null) {
            return null;
        } else if (c.isEmpty()) {
            return "[]";
        }

        return c.stream().map(t -> {
            try {
                return ThriftSerDePool.getSimpleJsonSerializer().toString(t);
            } catch (TException e) {
                LOG.warn("Failed to serialize object to JSON string", e);
                throw new RuntimeException(e);
            }
        }).collect(Collectors.joining(",", "[", "]"));
    } catch (Exception e) {
        LOG.warn("Failed to serialize object to JSON string", e);
        return "";
    }

}

有任何好主意，比如使用Jackson的Custom_Serializers

使用Collection <t extends =“”tbase =“”>进行序列化

0 个答案: