我正在尝试创建一个方法,用一个新字符替换单词中某个字符的所有实例。这就是我到目前为止所做的:
public class practice {
public static void main(String[] args) {
String test3 = updatePartialword("----", "test", 't');
System.out.println(test3); }
public static String updatePartialword(String partial, String secret, char c) {
String newPartial = "";
int len = secret.length();
for (int i=0; i<=secret.length()-1; i++){
char x = secret.charAt(i);
if (c==x) {
String first = partial.substring(0,i);
String second = partial.substring(i+1,len);
newPartial = first+x+second;
}
}
return newPartial;
}
}
我希望它返回t-t,但它只打印最后一个t。任何帮助将不胜感激!
答案 0 :(得分:3)
Java已经在String中有一个内置方法。您可以使用replace()
方法将字符串中给定字符的所有匹配项替换为另一个字符
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答案 1 :(得分:0)
我怀疑你正在寻找像
这样的东西public static void main(String[] args) {
String test3 = updatePartialword("----", "test", 't');
System.out.println(test3);
}
public static String updatePartialword(String partial, String secret, char c) {
char[] tmp = partial.toCharArray();
for (int i = 0; i < secret.length(); i++) {
char x = secret.charAt(i);
if (c == x) {
tmp[i] = c;
}
}
return new String(tmp);
}
答案 2 :(得分:0)
在您的代码中,每次找到该字符时都会覆盖String。您应该每次都扩展字符串,而不是覆盖。
public class practice {
public static void main(String[] args) {
String test3 = updatePartialword("----", "test", 't');
System.out.println(test3);
}
public static String updatePartialword(String partial, String secret, char c) {
StringBuilder sb = new Stringbuilder();
sb.append(""); // to prevent the Stringbuilder from calculating with the chars
for (int i = 0; i < partial.lenght; i++)
if (secret.charAt(i) == c)
sb.append(c);
else
sb.append('-');
return sb.toString();
}
}