typedef struct _ppm_struct* ppm_struct;
typedef unsigned char ppm_subpixel;
typedef ppm_subpixel (*ppm_pixel_func)(ppm_subpixel);
struct ppm_pixel {
ppm_subpixel red;
ppm_subpixel green;
ppm_subpixel blue;
};
struct _ppm_struct {
unsigned int width;
unsigned int height;
unsigned int max_color;
ppm_pixel *firstpixel;
};
所以我有这个函数调用:
void pppm_color_pixel(ppm_struct p, ppm_struct out, ppm_pixel_func func, int threads) {
//ppm_pixel_func func2 = &inverse_pixel;
unsigned int w = p->width;
unsigned int h = p->height;
ppm_pixel *iterator = p->firstpixel;
std::thread th[threads];
long long total_pixels = w*h;
unsigned int count_for_thread = total_pixels/threads;
for(int j = 0; j<threads; ++j) {
th[j] = std::thread(pppm_color_chunk_pixel,func, *iterator,count_for_thread);
iterator = &iterator[count_for_thread];
}
for(int j = 0; j<threads; ++j) {
th[j].join();
}
接下来的两个函数:funct是逆子像素
ppm_subpixel inverse_subpixel(ppm_subpixel subpixel) {
subpixel = 255- subpixel;
return subpixel;
}
void pppm_color_chunk_pixel(ppm_pixel_func func, ppm_pixel start_pixel, unsigned int count) {
ppm_pixel *iterator = &start_pixel;
for(unsigned int i = 0; i< count; ++i) {
iterator[i].red = func(iterator[i].red);
iterator[i].green = func(iterator[i].green);
iterator[i].blue = func(iterator[i].blue);
}
}
主要:
pppm_color_pixel(p,out, &inverse_subpixel,pppm_get_max_cores());
问题在于,当我运行它时,它会向我显示分段错误。这发生在这一行:
iterator[i].green = func(iterator[i].green);
当发生这种情况时,我真正不理解的是i = 2
或更多。它不会从第一次崩溃。即使我尝试只调用一个线程,结果也是一样的。
答案 0 :(得分:1)
pppm_color_chunk_pixel
接受ppm_pixel
的副本。由于它是按值复制的,因此将*iterator
传递给它只会导致复制一个元素。在&start_pixel
之后迭代任何内容都会失败。
由于std::thread
不通过引用传递对象,因此您还需要一个引用包装器。
void pppm_color_chunk_pixel(ppm_pixel_func func, ppm_pixel& start_pixel, unsigned int count) {
ppm_pixel* iterator = &start_pixel;
for (unsigned int i = 0; i < count; ++i) {
iterator[i].red = func(iterator[i].red);
iterator[i].green = func(iterator[i].green);
iterator[i].blue = func(iterator[i].blue);
}
致电:
for (int j = 0; j < threads; ++j) {
th[j] = std::thread(pppm_color_chunk_pixel, func, std::ref(*iterator), count_for_thread);
iterator = &iterator[count_for_thread];
}
我没有测试过,但我猜这是你的问题。