我正在尝试在我的Workflow脚本中包含外部代码,但我遗漏了一些东西。第一步似乎有效。如果路径无效,则失败:
evaluate( new File('/home/larry.fast/Wkflo.groovy'))
但我在下面尝试了一些语法变体,并没有找到有效的咒语。所有尝试都产生了“无法解析类mycode.Wkflo。
的变体def z = mycode.Wkflo()
Wkflo.groovy包含:
package mycode;
def hello() {
echo "Hello from workflow"
}
我也尝试过像run(File())或删除包声明这样的变体。
答案 0 :(得分:20)
Jenkins Workflow文档现在包含“加载脚本文本”部分 https://github.com/jenkinsci/workflow-plugin/blob/master/TUTORIAL.md但我发现很难遵循。这是一个简单的示例,演示了如何在外部文件中创建完整的工作流程和其他方法。
Jenkins中的工作流程代码:
// Loading code requires a NODE context
// But we want the code accessible outside the node Context
// So declare extcode (object created by the LOAD operation) outside the Node block.
def extcode
node {
// paths are relative to your workspace
// you may need to run git to populate your workspace
git url: 'ssh://mygitrepo'
extcode = load 'myExtCode.wkflo'
// or you can directly access the file system
// Eg. when developing your code in a local git clone
extcode = load '/some/absolute/path/myExtCode.wkflo'
// extcode is now a groovy object containing everything declared in the file
extcode.hello('world')
}
// If your code contains Stage and Node blocks,
// you'll want to initiate that code outside of the node() block above
extcode.extMain()
------ myExtCode.wkflo
// Any command placed at the root of the file get executed during the load operation
echo "hello from loading myExtCode"
// Methods declared in external code are accessible
// directly from other code in the external file
// indirectly via the object created by the load operation
// eg. extcode.hello('use this syntax from your main code')
def hello(whom) {
echo "Hello ${whom}"
}
// Complete workflows should be created inside a controlling method
// else they will run nested inside the node() block when the load takes place (edit: added missing "def" keyword
def extMain() {
stage 'External Code is running'
node() {
hello('from external node block')
}
}
// !!Important Boilerplate!!
// The external code must return it's contents as an object
return this;