SELECT category, SUM(price*amount);
FROM dan2.dbf WHERE;
between(date_p, {^2014-01-01}, {^2014-12-31});
GROUP BY category
此查询查找日期类别和某些条件的总和。我需要找到总和的最大值(由subkuery)。
答案 0 :(得分:2)
详细信息取决于您使用的VFP版本 - 在最新的VFP 9中,您可以执行类似
的操作* create test data
CREATE CURSOR test (id Int, category Int, price Num(15,2), amount Int, dateP D)
INSERT INTO test VALUES (1, 2, 24.25, 15, {^2014-10-5})
INSERT INTO test VALUES (2, 2, 700.0, 15, {^2014-7-25})
INSERT INTO test VALUES (3, 2, 110.10, 210, {^2015-11-15})
INSERT INTO test VALUES (4, 3, 110.10, 11, {^2014-11-15})
* your original
SELECT category, SUM(price*amount) ;
FROM test ;
WHERE datep Between {^2014-01-01} And {^2014-12-31} ;
GROUP BY category
* your desired result w/o sub-query
SELECT SUM(price*amount) ;
FROM test ;
WHERE datep Between {^2014-01-01} And {^2014-12-31}
* the desired sub-query you described
SELECT SUM(Total) ;
FROM ( ;
SELECT category, SUM(price*amount) As Total ;
FROM test ;
WHERE datep Between {^2014-01-01} And {^2014-12-31} ;
GROUP BY category ;
) As subQuery
编辑:
* as per your comment
SELECT TOP 1 category, Max(Total) ;
FROM ( ;
SELECT category, SUM(price*amount) As Total ;
FROM test ;
WHERE datep Between {^2014-01-01} And {^2014-12-31} ;
GROUP BY category ;
) As subQuery ;
GROUP BY 1 ;
ORDER BY 2 Desc
答案 1 :(得分:1)
我需要找到最大值
您可以通过单个查询轻松获取最大值和在查询上使用ORDER DESC然后获取TOP值。
SELECT category,
SUM(price*amount) AS Sum_Val;
FROM dan2.dbf WHERE;
between(date_p, {^2014-01-01}, {^2014-12-31});
GROUP BY category
ORDER BY 2 DESC
INTO CURSOR TmpResults
SELECT TmpResults
GO TOP
MaxSum = TmpResults.Sum_Val
祝你好运