我想为多客户端套接字程序编写代码, 但我得到了错误的文件描述符,我不知道如何解决它。 这是我在python中的第一个代码我是python中的新代码。
我的代码:
import socket
import os.path
from thread import *
host = '0.0.0.0'
port = 11111
#server_socket = socket.socket()
server_socket = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
server_socket.bind((host, port))
server_socket.listen(1)
def clientthread(client_socket):
while True:
rqst = client_socket.recv(1024)
if ("GET" not in rqst) or (rqst == ""):
client_socket.send("HTTP/1.1 500 Internal Server Error\r\n")
FileName = rqst.split(" ")[1]
print "Client (%s, %s) connected" % client_address
print rqst
if os.path.isfile(os.getcwd() + FileName) == True:
f = open(os.getcwd() + FileName )
g = f.read()
response = 'HTTP/1.1 200 OK\r\n' + 'Content-Length: ' + str(len(g)) + '\r\n''' + g
client_socket.send(response)
print response
elif FileName == "/":
f = open(os.getcwd() + "/index.html")
g = f.read()
response = 'HTTP/1.1 200 OK\r\n' + 'Content-Length: ' + str(len(g)) + '\r\n''' + g
client_socket.send(response)
print response
elif FileName == "/for.html":
client_socket.send("HTTP/1.1 403 Forbidden\r\n\r\n")
print "HTTP/1.1 403 Forbidden\r\n\r\n"
elif FileName == "/move.html":
f = open(os.getcwd() + "/index2.html")
g = f.read()
client_socket.send(g)
client_socket.send('HTTP/1.1 302 Moved Temporarily\r\n')
print 'moved''http/1.1 302 Moved Temporarily\r\n'
elif "calculate-next?num=" in FileName:
num = int(FileName[FileName.find("=")+1:])+1
client_socket.send(str(num))
print str(num)
elif "calculate-area?" in FileName:
height = float(FileName[FileName.find("height")+7:FileName.find("&")])
width = float(FileName[FileName.find("width")+6:])
S = float((height*width)/2)
client_socket.send(str(S))
print str(S)
else:
response = "HTTP/1.1 404 Not Found\r\n"
client_socket.send(response)
print response
client_socket.close()
client_socket.close()
server_socket.close()
while True:
(client_socket, client_address) = server_socket.accept()
start_new_thread(clientthread ,(client_socket,))
我的错误:
开始的线程中未处理的异常 Traceback(最近一次调用最后一次): 在clientthread中的文件“C:\ Users \ Eden \ Desktop \ HTTPserver \ server2.py”,第15行 rqst = client_socket.recv(1024) 文件“C:\ Python27 \ lib \ socket.py”,第174行,在_dummy中 引发错误(EBADF,'错误的文件描述符') socket.error:[Errno 9]错误的文件描述符
我该怎么办?
答案 0 :(得分:0)
你的内部while循环中有一个重复的client_socket.close()
行缩进。这意味着您尝试从已关闭的套接字接收数据,这会引发该错误。另外,为什么要关闭server_socket
方法中的clientthread
。