Question

我想在listView中处理EditText和一个按钮来发送短信。到目前为止，电话号码由用户输入。所以，我已经制作了一个适配器，如下所示：

public class ListViewStudentWithDateAdapter extends ArrayAdapter<ListViewStudentWithDate> {
private Context mContext;
private ArrayList<ListViewStudentWithDate> mData;
private EditText Parent_Number ;

public ListViewStudentWithDateAdapter (Context mContext, ArrayList<ListViewStudentWithDate> mData)
{
    super(mContext, R.layout.student_list_with_date_shape, mData);
    this.mContext = mContext;
    this.mData = mData;
}
public int getCount() {
    return mData.size();
}

@Override
public long getItemId(int position) {
    return position;
}

@Override
public View getView(final int position, View convertView, ViewGroup parent)
{
    if (convertView == null) {
        LayoutInflater mInflater = (LayoutInflater)
                mContext.getSystemService(Activity.LAYOUT_INFLATER_SERVICE);
        convertView = mInflater.inflate(R.layout.student_list_with_date_shape, null);
    }
    TextView Name  = (TextView) convertView.findViewById(R.id.Name);
    Name.setText(mData.get(position).getStudent_name());

    TextView GRADE  = (TextView) convertView.findViewById(R.id.GRADE_ID);
    GRADE.setText(mData.get(position).getGrade_id());

    TextView CLASS  = (TextView) convertView.findViewById(R.id.CLASS_ID);
    CLASS.setText(mData.get(position).getCLass_id());

    Parent_Number  = (EditText) convertView.findViewById(R.id.Father_number);

    Button Send_Father = (Button) convertView.findViewById(R.id.Send_Father);
    Send_Father.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View view) {
            Log.i("Send SMS", "");
            String phoneNo = Parent_Number.getText().toString();
            String sms = "HELLO World" ;
            try {
                // Get the default instance of the SmsManager
                SmsManager smsManager = SmsManager.getDefault();
                smsManager.sendTextMessage(phoneNo,
                        null,
                        sms,
                        null,
                        null);
                Toast.makeText(getContext(), "Your sms has successfully sent!",
                        Toast.LENGTH_LONG).show();
            } catch (Exception ex) {
                Toast.makeText(getContext(),"Your sms has failed...",
                        Toast.LENGTH_LONG).show();
                ex.printStackTrace();
            }
        }
    });
    return convertView;
}

 }

它似乎不起作用，因为它总是给我失败的信息。有什么想法??

Answer 1

检查你的清单是否持续：

<uses-permission android:name="android.permission.SEND_SMS" />

我认为你的电话号码是空的，调试它

Answer 2

您最有可能获得IllegalArgumentException，因为您传递给sendTextMessage()的号码为空。 Parent_Number是一个类成员，它将保留对getView()调用创建的最后一个实例的引用，Parent_Number不一定是您当前正在编辑的实例。

您需要在EditText Send_Father的代码上缓存Button onClick()，并在public View getView(final int position, View convertView, ViewGroup parent) { ... Parent_Number = (EditText) convertView.findViewById(R.id.Father_number); Button Send_Father = (Button) convertView.findViewById(R.id.Send_Father); Send_Father.setTag(Parent_Number); Send_Father.setOnClickListener(new View.OnClickListener() { @Override public void onClick(View view) { Log.i("Send SMS", ""); EditText parent = (EditText) view.getTag(); String phoneNo = parent.getText().toString(); String sms = "HELLO World" ; try { // Get the default instance of the SmsManager SmsManager smsManager = SmsManager.getDefault(); smsManager.sendTextMessage(phoneNo, null, sms, null, null); Toast.makeText(getContext(), "Your sms has successfully sent!", Toast.LENGTH_LONG).show(); } catch (Exception ex) { Toast.makeText(getContext(),"Your sms has failed...", Toast.LENGTH_LONG).show(); ex.printStackTrace(); } } }); return convertView; }方法中检索它及其文字：< / p>

public class LoginNarrowActivity extends BaseActivity implements LoginFragment.CallBacks {
@Override
protected void onCreate(Bundle savedState){
    super.onCreate(savedState);
    setContentView(R.layout.activity_login_narrow);

    LoginFragment loginFragment = (LoginFragment)getSupportFragmentManager().findFragmentById(R.id.your_fragment_id);
    loginFragment.setCallBacks(this);
}

处理Button和EditText以发送SMS

2 个答案: