如何检查客户端是否加入了组播组?

时间:2015-11-14 06:01:57

标签: c sockets udp multicast

结束目标:

服务器的父进程知道哪些客户端加入或离开多播组。到目前为止,我只是试图检查加入的客户,因为我认为检查离开是一件类似的问题。

我的方法到目前为止:

通过select()检查多播组套接字的更改。

加入后,客户端执行指向服务器程序(父进程)的sendto()。服务器中的select()旨在识别任何更改,但显然不会,因此retval != 0永远不会成立。

到目前为止的结果

我尝试过许多不同的IP地址和常量,例如INADDR_ANY,但我只管理通过多播将消息发送回客户端,并且这个解释就像服务器程序一样发了它。最常见的结果是服务器程序根本没有收到任何消息。

这是我的客户代码:

/* Receiver/client multicast Datagram*/
#include <sys/types.h>
#include <sys/socket.h>
#include <arpa/inet.h>
#include <netinet/in.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

#define MAX_MSG 100

struct sockaddr_in localSock, servSock;
struct ip_mreq group;
int sd, n;
int datalen, mcastport;
char msg[MAX_MSG];

int main(int argc, char *argv[])
{

    if(argc!=3) {
        printf("usage : %s <address> <port>\n",argv[0]);
        exit(0);
    }

    mcastport = atoi(argv[2]);


    /* Create a datagram socket on which to receive. */
    sd = socket(AF_INET, SOCK_DGRAM, 0);
    if(sd < 0)
    {
        perror("Opening datagram socket error");
        exit(1);
    }
    else
        printf("Opening datagram socket....OK.\n");

    /* Enable SO_REUSEADDR to allow multiple instances of this */
    /* application to receive copies of the multicast datagrams. */
    {
        int reuse = 1;
        if(setsockopt(sd, SOL_SOCKET, SO_REUSEADDR, (char *)&reuse, sizeof(reuse)) < 0)
        {
            perror("Setting SO_REUSEADDR error");
            close(sd);
            exit(1);
        }
        else
            printf("Setting SO_REUSEADDR...OK.\n");
    }

    /* Bind to the proper port number with the IP address */
    /* specified as INADDR_ANY. */
    memset((char *) &localSock, 0, sizeof(localSock));
    localSock.sin_family = AF_INET;
    localSock.sin_port = htons(mcastport);
    localSock.sin_addr.s_addr = INADDR_ANY;
    if(bind(sd, (struct sockaddr*)&localSock, sizeof(localSock)))
    {
        perror("Binding datagram socket error");
        close(sd);
        exit(1);
    }
    else
        printf("Binding datagram socket...OK.\n");

    printf("Enter the group's name you want to join:\n");
    scanf("%s", msg);

    /* Join the multicast group 226.1.1.1 on the local IP address */
    /* interface. Note that this IP_ADD_MEMBERSHIP option must be */
    /* called for each local interface over which the multicast */
    /* datagrams are to be received. */
    group.imr_multiaddr.s_addr = inet_addr(argv[1]);
    group.imr_interface.s_addr = inet_addr("127.0.0.1");
    if(setsockopt(sd, IPPROTO_IP, IP_ADD_MEMBERSHIP, (char *)&group, sizeof(group)) < 0)
    {
        perror("Adding multicast group error");
        close(sd);
        exit(1);
    }
    else
        printf("Adding multicast group...OK.\n");

    /* Initialize the group sockaddr structure with a */
    /* group address of 226.1.1.1 and port given by user. */
    memset((char *) &servSock, 0, sizeof(servSock));
    servSock.sin_family = AF_INET;
    servSock.sin_addr.s_addr = inet_addr(argv[1]);
    servSock.sin_port = htons(mcastport);

    if(sendto(sd, "", 1, 0, (struct sockaddr*) &servSock, sizeof(servSock)) < 0)
    {perror("Sending datagram message error");}
    else
        printf("Sending datagram message...OK\n");

    /* Read from the socket. */
    if((n=read(sd, msg, MAX_MSG)) < 0)
    {
        perror("Reading datagram message error");
        close(sd);
        exit(1);
    }
    else
    {
        printf("Reading datagram message...OK.\n");
        printf("The message from multicast server is: \"%s\"\n", msg);
    }

    msg[n] = '\0';

    return 0;
}

这是我的服务器程序代码:

/* Send Multicast Datagram code*/
#include <sys/types.h>
#include <sys/ioctl.h>
#include <net/if.h>
#include <sys/socket.h>
#include <arpa/inet.h>
#include <netinet/in.h>
#include <stdio.h>
#include <stdlib.h>

#include <stdio.h>
#include <unistd.h>
#include <string.h> /* for strncpy, memset */

#define MAX_MSG 100

struct in_addr localInterface;
struct sockaddr_in groupSock, cliAddr;
int sd, mcastport, maxJoin, maxJoined = 0, pipefd[2], cliLen, cpid;
char msg[MAX_MSG], groupName[MAX_MSG];

int main (int argc, char *argv[ ])
{


    /* check command line args */
    if(argc < 2) {
        printf("usage : %s <port> \n", argv[0]);
        exit(1);
    }

    mcastport = atoi(argv[1]);

    /* Create a datagram socket on which to send. */
    sd = socket(AF_INET, SOCK_DGRAM, 0);
    if(sd < 0)
    {
        perror("Opening datagram socket error");
        exit(1);
    }
    else
        printf("Opening the datagram socket...OK\n");

    /* Initialize the group sockaddr structure with a */
    /* group address of 225.1.1.1 and port given by user. */
    memset((char *) &groupSock, 0, sizeof(groupSock));
    groupSock.sin_family = AF_INET;
    groupSock.sin_addr.s_addr = inet_addr("226.1.1.1");
    groupSock.sin_port = htons(mcastport);

    printf("Create a group: ");
    scanf("%s", groupName);

    printf("Maximum number of clients that can join the group? ");
    scanf("%d", &maxJoin);

    /* Disable loopback so you do not receive your own datagrams.
    {
    char loopch = 0;
    if(setsockopt(sd, IPPROTO_IP, IP_MULTICAST_LOOP, (char *)&loopch, sizeof(loopch)) < 0)
    {
    perror("Setting IP_MULTICAST_LOOP error");
    close(sd);
    exit(1);
    }
    else
    printf("Disabling the loopback...OK.\n");
    }
     */

    /* Set local interface for outbound multicast datagrams. */
    /* The IP address specified must be associated with a local, */
    /* multicast capable interface. */
    printf("Setting the local interface...");
    localInterface.s_addr = inet_addr("127.0.0.1");
    if(setsockopt(sd, IPPROTO_IP, IP_MULTICAST_IF, (char *)&localInterface, sizeof(localInterface)) < 0)
    {
        perror("error");
        exit(1);
    }
    else
        printf("OK\n");



    if((cpid = fork()) == 0) //child process --sends messages
    {
        /* Send a message to the multicast group specified by the*/
        /* groupSock sockaddr structure. */
        printf("Enter a message to send: \n");
        scanf("%s", msg);

        if(sendto(sd, msg, strlen(msg)+1, 0, (struct sockaddr*)&groupSock, sizeof(groupSock)) < 0)
        {perror("Sending datagram message error");}
        else
            printf("Sending datagram message...OK\n");

        /* Try the re-read from the socket if the loopback is not disable
        if(read(sd, databuf, datalen) < 0)
        {
        perror("Reading datagram message error\n");
        close(sd);
        exit(1);
        }
        else
        {
        printf("Reading datagram message from client...OK\n");
        printf("The message is: %s\n", databuf);
        }
         */

        exit(EXIT_SUCCESS);
    }
    else //parent process --checks for JOINs and QUITs
    {
        fd_set rfds;
        struct timeval tv;
        int retval, status;

        while (waitpid(cpid, &status, WNOHANG) != cpid)
        {
            /* Watch stdin (fd 0) to see when it has input. */
            FD_ZERO(&rfds);
            FD_SET(sd, &rfds);

            /* Wait up to five seconds. */
            tv.tv_sec = 5;
            tv.tv_usec = 0;

            retval = select(sd+1, &rfds, NULL, NULL, &tv);
            /* Don't rely on the value of tv now! */

            if (retval == -1)
                perror("select()");
            else if (retval != 0)
            {
                printf("Data is available now.\n");
                /* FD_ISSET(0, &rfds) will be true. */

                cliLen = sizeof(cliAddr);
                int n;
                if((n = recvfrom(sd, msg, MAX_MSG, 0, (struct sockaddr *) &cliAddr,&cliLen)) == -1)
                    perror("Some bullshit happened");
                msg[n] = '\0';

                printf("Client IP:port is: %s:%d", inet_ntoa(cliAddr.sin_addr), (int) ntohs(cliAddr.sin_port));
            } else
            {printf("no data.\n");}
        }
        exit(0);
    }
    return 0;
}

可能的解决方案我没有尝试过: 也许我不应该使用多播组来发送信息客户端 - >服务器,而是另一种类型的连接?我只是在这里猜测。我知道你们不喜欢做任何人的工作。

我一直在这&#34;简单&#34;问题几个小时,我尽可能地阅读,包括this question这似乎非常相似,但我无法以任何方式解决它。我完全在这里罢工。

2 个答案:

答案 0 :(得分:1)

可能有助于你的两点:

  • 如果您的通信只是本地通信(在代码中使用127.0.0.1),则无需使用多播
  • 多播组由网络接口​​加入,而不是由进程加入。一旦网络接口加入了多播接口,第二次将同一网络接口加入同一个多播组将不会改变任何内容。即使它是在同一主机上请求第二个进程的另一个进程 接合。

答案 1 :(得分:1)

如果客户端发送到组播组并且服务器希望读取该组播组,则服务器也需要加入组播组。

这不是一个很好的解决方案,因为所有其他客户端成员也将收到该多播。

客户端首先从服务器接收多播,然后响应服务器的地址,这是更有意义的。通过recvfrom()的结果参数。