Question

对于上课，我必须编写一个计算12个不同等级＆＃34;的程序。我使用了2个不同的数组 - ＆＃34;分子[]＆＃34;和＆＃34;分母[]＆＃34;每个都有12个（12个不同的整数）。对于这个赋值，我必须使分母0的值为3，这表明这些分母的相应分子等于＆＃34;奖励积分＆＃34; （例如5/0级将等于5个奖励积分）。但是，现在我必须创建一个＆＃34;数据清理＆＃34;函数，它使用非零分母获取所有分数，并将它们移动到一个新的空数组（只留下＆＃34;真实＆＃34;分数，我作为newNumerator []和newDenominator []，以及每个数组的新大小＆＃34; newSize＆＃34;。数据清理功能需要具有这些参数 -

dataClean(int numerator[], int denominator[], int size, int newNumerator[], int newDenominator[], int &newSize)

我需要填充新数组并在cleanData函数中定义那些数组的newSize，并让它们的新值通过参数返回到main（）。但是，我已经坚持了很长一段时间。我不确定是否需要使用指针，即使如此，我也不清楚如何使用它们。很抱歉，如果不清楚，这项任务对我来说非常困惑。任何帮助表示赞赏。如果您需要任何进一步的澄清，请告诉我。

分子和分母的数据文件（data.txt）

72 49 23 5 9 10 6 16 26 54 4 55//numerator[]
75 50 25 0 10 0 0 20 30 55 5 60//denominator[]

程序 -

#include <iostream>
#include <fstream>
#include <cstdlib>
#include <string>
#include <cmath>
#include <iomanip>

using namespace std;

typedef int arrayType[];

void readData(int numerator[], int denominator[], int size);
void reportData(arrayType, arrayType, int);
void reportOverall(int numerator[], int denominator[], int size);
void cleanData(int numerator[], int denominator[], int size, int newNumerator[], int newDenominator[], int &newSize);
int main()
{
    const int size = 12;
    int numerator[size];
    int denominator[size];
    int newSize = 12;
    int newNumerator[newSize];
    int newDenominator[newSize];


    cout << fixed << showpoint << setprecision(1);

    readData(numerator, denominator, size);

    reportData(numerator, denominator, size);

    reportOverall(numerator, denominator, size);

    cout << "\n******************************\n";

    cleanData(numerator, denominator, size, newNumerator, newDenominator, &newSize);
    reportData(newNumerator, newDenominator, newSize);

    system("pause");
    return 0;
}

void readData(int numerator[], int denominator[], int size)
{
    ifstream dataIn;
    dataIn.open("data.txt");
    if(!dataIn)
    {
        cout << "File not found\n";
        system("pause");
        exit(1);
    }

    int count;
    for(count = 0; count < size; count++)
    {
        dataIn >> numerator[count];
    }
    for (count = 0; count < size; count++)
    {
        dataIn >> denominator[count];
    }

    dataIn.close();
}

void reportData(arrayType numerator, arrayType denominator, int size)
{
    int count;
    for (count = 0; count < size; count++)
    {
        if (denominator[count] == 0)
        {
            cout << "Score " << (count + 1) << " is " << numerator[count] << "/" << denominator[count] << " = " << "Bonus points!\n";
        }
        else
        {
            double percent = 100.0 * static_cast<double>(numerator[count]) / denominator[count];
            cout << "Score " << (count + 1) << " is " << numerator[count] << "/" << denominator[count] << " = " << (percent) << "%\n";
        }
    }
}

void reportOverall(int numerator[], int denominator[], int size)
{
    int count;
    int totalNumerator = 0.0;
    int totalDenominator = 0.0;

    for (count = 0; count < size; count++)
    {
        totalNumerator += numerator[count];
    }
    for (count = 0; count < size; count++)
    {
        totalDenominator += denominator[count];
    }

    double overallPercent = 100.0 * static_cast<double>(totalNumerator) / (totalDenominator);
    cout << "Total Points Earned (numerators): " << totalNumerator << endl;
    cout << "Total Points Possible (denominators): " << totalDenominator << endl;
    cout << "Overall Grade: " << overallPercent << "%\n";
}

void cleanData(int numerator[], int denominator[], int size, int *newNumerator[], int *newDenominator[], int &newSize)
{
    int count;

    for(count = 0; count < size; count++)
    {
        int count2 = 0;
        if(denominator[count] != 0)
        {
            *newNumerator[count2] = numerator[count];
            *newDenominator[count2] = denominator[count];
            newSize--;
            count2++;
        }
    }

}

Answer 1

你需要通过适当的参数引用来修复函数调用和cleanData定义

within main:

cleanData(numerator, denominator, size, newNumerator, newDenominator, newSize);


void cleanData(int* numerator, int* denominator, const int size, int *newNumerator, int *newDenominator, int newSize)
{
int count;

    for(count = 0; count < size; count++)
    {
        int count2 = 0;
        if(denominator[count] != 0)
        {
            newNumerator[count2] = numerator[count];
            newDenominator[count2] = denominator[count];
            newSize--;
            count2++;
        }
    }
}

C ++在void函数中填充空数组

1 个答案: