我正在导入具有以下格式的CSV文件:
5021 2510 0600 1234 560,50,SLM
5021 2510 0600 1234 570,50,SLM
5021 2510 0600 1234 580,50,SLM
删除空格后,我能够将数据回显到3列表。我想要做的是从第一列编号" 5021251006001234560"中提取,只是段" 123456",然后追加" 123456"到CSV行数组的col [3]。我认为我在代码中的评论可能有助于解释我想要实现的目标。
我想我之后的内容是CSV文件中的多维数组,如下所示:
5021251006001234560,50,SLM,123456
5021251006001234570,50,SLM,123457
5021251006001234580,50,SLM,123458
这样我就可以逐行访问4个值。到目前为止,这是我的代码:
$csv = array();
if (($file = fopen("uploads/" . $_FILES["file"]["name"], 'r')) === false)
{
throw new Exception('There was an error loading the CSV file.');
}
else
{
while (($line = fgetcsv($file, 1000)) !== false)
{
$csv[] = $line;
}
fclose($handle);
}
echo "<table>";
foreach ($csv as $rows => $row)
{
echo "<tr>";
foreach ($row as $col => $cell)
{
$serial = '000000';
$cell = preg_replace('/\s+/', '', $cell);
// Check if the $cell value contains "50212510" at the start
$findme = "50212510";
if (strpos($cell, $findme) === true) {
// Get the 6 digits before the last digit
$serial = substr($cell, 11, 6);
// And append the 6 digits as a forth[3] value to each CSV row
array_push($row, $serial);
}
echo "<td>" . $cell . "</td>";
if ($cell === "SLM") {
echo "<td>" . $serial ."</td>";
}
}
echo "</tr>";
}
echo "<table>";
任何帮助都将不胜感激。
答案 0 :(得分:0)
我有答案。像很多次一样,拼出问题,实现了答案。
foreach($array as $line)
{
foreach( $line as $cell )
{
if (substr($cell, 0, 8) === "50212510") {
$serial = substr($cell, -7, 6);
}
}
}