//Write a program that will input letter grades (A, B, C, D, F), the number of
//which is input by the user (a maximum of 50 grades). The grades will be read
//into an array. A function will be called five times (once for each letter grade)
//and will return the total number of grades in that category. The input to the
//function will include the array, number of elements in the array and the letter
//category (A, B, C, D or F). The program will print the number of grades that
//are A, B, etc.
#include <iostream>
using namespace std;
double countGrade(char letterCategory, int size, char array);
const int SIZE = 5;
char letterCategory[SIZE] = {'A', 'B', 'C', 'D', 'F'};
char userLetters[50];
int main()
{
// Declare Variables
int numberOfGrades = 0;
int gradeNumbersA = 0;
int gradeNumbersB = 0;
int gradeNumbersC = 0;
int gradeNumbersD = 0;
int gradeNumbersF = 0;
// Get the number of grades to be read
cout << "Please input the number of grades to be read in. (1-50): ";
cin >> numberOfGrades;
// Input Validation
if(numberOfGrades < 1 || numberOfGrades > 50)
{
cout << "Error! Invalid Input. Please enter a number between 1 and 50.\n";
cin >> numberOfGrades;
}
while(numberOfGrades < 1 || numberOfGrades > 50);
cout << "All grades must be upper case A B C D or F.\n";
// Get the grade
{
for(int i = 0; i < numberOfGrades; i++)
{
cout << "Input a grade: ";
cin >> userLetters[i];
}
}
// Output the number in each category
cout << "Number of A: " << gradeNumbersA << endl;
cout << "Number of B: " << gradeNumbersB << endl;
cout << "Number of C: " << gradeNumbersC << endl;
cout << "Number of D: " << gradeNumbersD << endl;
cout << "Number of F: " << gradeNumbersF << endl;
return 0;
}
double countGrade(char letterCategory, int size, char array)
{
for(int count = 0; count < 5; count++)
{
int a = 0, b = 0, c = 0, d = 0, f = 0;
switch(array)
{
case 'A':
a++;
return a;
break;
case 'B':
b++;
return b;
break;
case 'C':
c++;
return c;
break;
case 'D':
d++;
return d;
break;
case 'F':
f++;
return f;
break;
}
}
}
我很难搞清楚这一个。我不太确定如何在main函数中调用countGrade函数。我知道我在这个程序的其他地方搞砸了,但我真的很感激帮助。
答案 0 :(得分:2)
您不需要切换声明。只需将数组元素中的等级与参数中的等级进行比较即可。并且你不应该返回总数直到函数结束。
,只要您匹配一个成绩,就会在循环中返回。int countGrade(char letterCategory, int size, char array[]) {
int total = 0;
for (int count = 0; count < size; count++) {
if (array[count] == letterCategory) {
total++;
}
}
return total;
}
然后在main()
中你做:
int numberOfGradesA = countGrade('A', numberOfGrades, userLetters);
和其他等级相似。