用Arrays调用函数 - C ++

时间:2015-11-14 00:55:24

标签: c++ arrays function

//Write a program that will input letter grades (A, B, C, D, F), the number of 
//which is input by the user (a maximum of 50 grades). The grades will be read 
//into an array. A function will be called five times (once for each letter grade) 
//and will return the total number of grades in that category. The input to the 
//function will include the array, number of elements in the array and the letter
//category (A, B, C, D or F). The program will print the number of grades that 
//are A, B, etc.

#include <iostream>
using namespace std;

double countGrade(char letterCategory, int size, char array);

const int SIZE = 5;
char letterCategory[SIZE] = {'A', 'B', 'C', 'D', 'F'};
char userLetters[50];

int main()
{
    // Declare Variables
    int numberOfGrades = 0;
    int gradeNumbersA = 0;
    int gradeNumbersB = 0;
    int gradeNumbersC = 0;
    int gradeNumbersD = 0;
    int gradeNumbersF = 0;

    // Get the number of grades to be read
    cout << "Please input the number of grades to be read in. (1-50): ";
    cin >> numberOfGrades;

        // Input Validation
        if(numberOfGrades < 1 || numberOfGrades > 50)
        {
            cout << "Error! Invalid Input. Please enter a number between 1 and 50.\n";
            cin >> numberOfGrades;
        }
        while(numberOfGrades < 1 || numberOfGrades > 50);

        cout << "All grades must be upper case A B C D or F.\n";

    // Get the grade
    {
        for(int i = 0; i < numberOfGrades; i++)
        {
            cout << "Input a grade: ";
            cin >> userLetters[i];
        }
    }

    // Output the number in each category
    cout << "Number of A: " << gradeNumbersA << endl;
    cout << "Number of B: " << gradeNumbersB << endl;
    cout << "Number of C: " << gradeNumbersC << endl;
    cout << "Number of D: " << gradeNumbersD << endl;
    cout << "Number of F: " << gradeNumbersF << endl;

    return 0;
}

double countGrade(char letterCategory, int size, char array)
{
    for(int count = 0; count < 5; count++)
    {
        int a = 0, b = 0, c = 0, d = 0, f = 0;

        switch(array)
        {
        case 'A':
            a++;
            return a;
            break;
        case 'B':
            b++;
            return b;
            break;
        case 'C':
            c++;
            return c;
            break;
        case 'D':
            d++;
            return d;
            break;
        case 'F':
            f++;
            return f;
            break;
        }
    }
}

我很难搞清楚这一个。我不太确定如何在main函数中调用countGrade函数。我知道我在这个程序的其他地方搞砸了,但我真的很感激帮助。

1 个答案:

答案 0 :(得分:2)

您不需要切换声明。只需将数组元素中的等级与参数中的等级进行比较即可。并且你不应该返回总数直到函数结束。

,只要您匹配一个成绩,就会在循环中返回。

int countGrade(char letterCategory, int size, char array[]) {
    int total = 0;
    for (int count = 0; count < size; count++) {
        if (array[count] == letterCategory) {
            total++;
        }
    }
    return total;
}

然后在main()中你做:

int numberOfGradesA = countGrade('A', numberOfGrades, userLetters);

和其他等级相似。