我今天一直在努力尝试将此示例改为POST数据而不是提供的示例GET。
我已经取代了这条线:
request.Method = HttpMethod.Get;
用
request.Method = HttpMethod.Post;
但是找不到允许我在我希望发布的内容中流式传输的方法。
这个HttpWebRequest似乎比其他方式更清洁,例如发送委托函数来处理响应。
在Wigley先生的示例代码中,我可以看到POST,所以它必须是可能的
public static class HttpMethod
{
public static string Head { get { return "HEAD"; } }
public static string Post { get { return "POST"; } }
答案 0 :(得分:0)
我前段时间写过这门课
public class JsonSend<I, O>
{
bool _parseOutput;
bool _throwExceptionOnFailure;
public JsonSend()
: this(true,true)
{
}
public JsonSend(bool parseOutput, bool throwExceptionOnFailure)
{
_parseOutput = parseOutput;
_throwExceptionOnFailure = throwExceptionOnFailure;
}
public async Task<O> DoPostRequest(string url, I input)
{
var client = new HttpClient();
CultureInfo ci = new CultureInfo(Windows.System.UserProfile.GlobalizationPreferences.Languages[0]);
client.DefaultRequestHeaders.Add("Accept-Language", ci.TwoLetterISOLanguageName);
var uri = new Uri(string.Format(
url,
"action",
"post",
DateTime.Now.Ticks
));
string serialized = JsonConvert.SerializeObject(input);
StringContent stringContent = new StringContent(
serialized,
Encoding.UTF8,
"application/json");
var response = client.PostAsync(uri, stringContent);
HttpResponseMessage x = await response;
HttpContent requestContent = x.Content;
string jsonContent = requestContent.ReadAsStringAsync().Result;
if (x.IsSuccessStatusCode == false && _throwExceptionOnFailure)
{
throw new Exception(url + " with POST ends with status code " + x.StatusCode + " and content " + jsonContent);
}
if (_parseOutput == false){
return default(O);
}
return JsonConvert.DeserializeObject<O>(jsonContent);
}
public async Task<O> DoPutRequest(string url, I input)
{
var client = new HttpClient();
CultureInfo ci = new CultureInfo(Windows.System.UserProfile.GlobalizationPreferences.Languages[0]);
client.DefaultRequestHeaders.Add("Accept-Language", ci.TwoLetterISOLanguageName);
var uri = new Uri(string.Format(
url,
"action",
"put",
DateTime.Now.Ticks
));
string serializedObject = JsonConvert.SerializeObject(input);
var response = client.PutAsync(uri,
new StringContent(
serializedObject,
Encoding.UTF8,
"application/json"));
HttpResponseMessage x = await response;
HttpContent requestContent = x.Content;
string jsonContent = requestContent.ReadAsStringAsync().Result;
if (x.IsSuccessStatusCode == false && _throwExceptionOnFailure)
{
throw new Exception(url + " with PUT ends with status code " + x.StatusCode + " and content " + jsonContent);
}
if (_parseOutput == false){
return default(O);
}
return JsonConvert.DeserializeObject<O>(jsonContent);
}
}
然后,当我想调用它时,我可以使用它如下:
JsonSend<User, RegistrationReceived> register = new JsonSend<User, RegistrationReceived>();
RegistrationReceived responseUser = await register.DoPostRequest("http://myurl", user);