Question

我有一个查询，它给出了以下输出：

AcctName                 budget 
Gross Salaries           232332
Basic Salaries           23123
Local Salaries           2312312
Local Travel             23424
country Travel           32242
Health care supplies     234234
Goods Supplies           3243242

您可以在此表中看到我有三个常用名称，例如Salaries，Travel，Supplies及其budget。我想查询可以给我以下结果：

AcctNAme      Budget
Salaries       232323423
Travel         323232332
Supplies       232323232

budget应为salaries，travel和supplies的总和。

修改

SELECT T1.[AcctName], T0.[DebLTotal]
FROM (VALUES('Salaries'),('Travel'),('Supplies')) TT1(AcctName)
LEFT JOIN(
SELECT CASE WHEN T1.[AcctName] LIKE '%Salaries%' THEN 'Salaries'
            WHEN T1.[AcctName] LIKE '%Travel%' THEN 'Travel'
            WHEN T1.[AcctName] LIKE '%Supplies%' THEN 'Supplies' END AS ActNAme,
       SUM(T0.[DebLTotal]) AS budget 
FROM OBGT T0 
   INNER JOIN OACT T1 ON T0.[AcctCode] = T1.[AcctCode] 
   INNER JOIN OBGS T2 ON T0.[Instance] = T2.[AbsId]
GROUP BY CASE WHEN T1.[AcctName] LIKE '%Salaries%' THEN 'Salaries'
              WHEN T1.[AcctName] LIKE '%Travel%' THEN 'Travel'
              WHEN T1.[AcctName] LIKE '%Supplies%' THEN 'Supplies' END) TT2 ON TT1.[AcctName] = TT2.[AcctName]

Answer 1

这应该可以正常工作。

select 'Salaries' as AcctName, (select sum(budget)
                                  from myTable
                                 where lower(AcctName) like '%salaries%') as Budget
union
select 'Travel', (select sum(budget)
                    from myTable
                   where lower(AcctName) like '%travel%')
union
select 'Supplies', (select sum(budget)
                      from myTable
                     where lower(AcctName) like '%supplies%')

您可以 test it here

我使用lower()进行不区分大小写的比较。很多时候，这不是必需的，具体取决于您如何定义数据库Collation。

Answer 2

您可以使用条件分组，如：

DECLARE @t TABLE
    (
      AcctName VARCHAR(100) ,
      budget INT
    )

INSERT  INTO @t
VALUES  ( 'Gross Salaries', 232332 ),
        ( 'Basic Salaries', 23123 ),
        ( 'Local Salaries', 2312312 ),
        ( 'Local Travel', 23424 ),
        ( 'country Travel', 32242 ),
        ( 'Health care supplies', 234234 ),
        ( 'Goods Supplies', 3243242 )

SELECT CASE WHEN AcctName LIKE '%Salaries%' THEN 'Salaries'
            WHEN AcctName LIKE '%Travel%' THEN 'Travel'
            WHEN AcctName LIKE '%Supplies%' THEN 'Supplies' 
            ELSE 'Other' END AS AcctNAme,
       SUM(budget) AS budget 
FROM @t
GROUP BY CASE WHEN AcctName LIKE '%Salaries%' THEN 'Salaries'
              WHEN AcctName LIKE '%Travel%' THEN 'Travel'
              WHEN AcctName LIKE '%Supplies%' THEN 'Supplies' 
              ELSE 'Other' END

编辑：

SELECT t.AcctNAme, l.budget
FROM (VALUES('Salaries'),('Travel'),('Supplies')) t(AcctNAme)
LEFT JOIN(
SELECT CASE WHEN AcctName LIKE '%Salaries%' THEN 'Salaries'
            WHEN AcctName LIKE '%Travel%' THEN 'Travel'
            WHEN AcctName LIKE '%Supplies%' THEN 'Supplies' END AS AcctNAme,
       SUM(budget) AS budget 
FROM @t
GROUP BY CASE WHEN AcctName LIKE '%Salaries%' THEN 'Salaries'
              WHEN AcctName LIKE '%Travel%' THEN 'Travel'
              WHEN AcctName LIKE '%Supplies%' THEN 'Supplies' END) l ON t.AcctNAme = l.AcctNAme

Answer 3

您使用int sumOfDigits(int n) { if(n<=9) return n; else { int r=0; while(n!=0) { r=r+n%10; n=n/10; } sumOfDigits(r); } }和REVERSE功能来反转RIGHT

示例：

ActName

您可以尝试以下代码：

SELECT RIGHT(S, CHARINDEX(' ', REVERSE(S)))FROM(
SELECT 'Health care supplies' AS S) AS A

-- Result

supplies

不同行的SQL查询作为一行

3 个答案: