函数返回Array但输出不是预期的

Question

我遇到的问题是我试图从函数EnterNumber()返回一个数组并将其显示在主数据库中，但它的出现相当疯狂。我使用了调试器，调试器中的数字是正确的，一旦打印到屏幕上就不正确。

我意识到我的程序中有一个全局const int，但是我的教授认可它，我希望我们这次只为这个程序做这件事。

正在寻找一个错误的原因。谢谢。

#include <iostream>

using namespace std;

void EnterNumber(int Number[]);

const int SIZE=20;

int main()
{
    int LargeNumber1[SIZE];
    int LargeNumber2[SIZE];

    for (int Counter1=0; Counter1<=19; ++Counter1)//zeros arrays out
    {
        LargeNumber1[Counter1]=0;
        LargeNumber2[Counter1]=0;
    }

    EnterNumber(LargeNumber1);

    for (int Counter2=0; Counter2<=19; ++Counter2)//display array 1 contents
    {
        cout << LargeNumber1[SIZE];
    }

    cout << "\n\n";

    EnterNumber(LargeNumber2);

    for (int Counter2=0; Counter2<=19; ++Counter2)//display array 2 contents
    {
        cout << LargeNumber2[SIZE];
    }

}

void EnterNumber(int Number[])
{
    int TemporaryArray[SIZE];
    int PlaceCounter;

    char Storage;

    PlaceCounter=0;

    for (int Counter1=0; Counter1<=19; ++Counter1)//zeros arrays out
    {
        TemporaryArray[Counter1]=0;
        Number[Counter1]=0;
    }

    cout << "Please enter a large number --> ";

    cin.get(Storage);

    while (Storage!='\n' && PlaceCounter<SIZE)//puts number in temp array - left aligned
    {
        TemporaryArray[PlaceCounter]=(Storage-'0');
        ++PlaceCounter;
        cin.get(Storage);
    }

    --PlaceCounter;//decrement one to get it to work properly with element style counting, else, extra zero at end

    for (int A=SIZE-1; PlaceCounter>=0; A--, PlaceCounter--)//transfers old array into new array, right aligned
    {
        Number[A]=TemporaryArray[PlaceCounter];
    }

    cout << "\n";
}

Answer 1

此：

for (int Counter2=0; Counter2<=19; ++Counter2)
{
    cout << LargeNumber1[SIZE];
}

应该是这样的：

for (int Counter2=0; Counter2<SIZE; ++Counter2)
{
    cout << LargeNumber1[Counter2];
}

您反复打印一个超出阵列末尾的数字。