Question

所以我有一个方法可以创建一个包含100个随机生成的字符的数组。

这是：

//method to generate random character between ch1 and ch2
   public static char getRandomCharacter(char ch1, char ch2)
   {

      return (char) (ch1 + Math.random() * (ch2 -ch1 +1));

   }

//==========================================   

   //method to assign generated characters (between a and z) to a 100 character array
   public static char[] createArray()
   {

      //declare a 100 character array
      char[] character = new char[100];

      //for loop assigning the random characters to the array using getRandomCharacter method
      for (int x = 0; x < character.length; x++)
      character[x] = getRandomCharacter('a', 'z');

      //for loop outputting the characters in the array
      for (int x = 0; x < character.length; x++)
      System.out.println(character[x]);

      return character;

   }

现在我需要创建一个获取100个生成字符的方法，并计算每个元音生成的次数。我坚持这个。

这是我到目前为止所做的：

public static void countArray()
   {

      int vowelA, vowelE, vowelI, vowelO, vowelU, vowelY;
      int elsePlaceHolder = 0;

      for (int x = 0; x < 100; x++)
      {

         if ((createArray()) == ('a'))
         vowelA++;

         else if ((createArray()) == ('e'))
         vowelE++;

         else if ((createArray()) == ('i'))
         vowelI++;

         else if ((createArray()) == ('o'))
         vowelO++;

         else if ((createArray()) == ('u'))
         vowelU++;

         else if ((createArray()) == ('y'))
         vowelY++;

         else
         elsePlaceHolder++;

      }

我认为使用for循环执行此操作是正确的，但我认为我没有正确执行它。一旦执行，我可以使用int变量显示元音计数的次数。那个elsePlaceHolder变量就在那里，因为我不知道如何处理else语句。

有人能用countArray()方法指出我正确的方向吗？非常感谢！

Answer 1

我认为你应该修改上面的代码！

public static void countArray()
{

  int vowelA=0, vowelE=0, vowelI=0, vowelO=0, vowelU=0, vowelY=0;
  int elsePlaceHolder = 0;
  char [] arr = new char[100];
  arr=createArray();
  for (int x = 0; x < 100; x++)
  {

     if (arr[x] == 'a')
     vowelA++;

     else if (arr[x] == 'e')
     vowelE++;

     else if (arr[x] == 'i')
     vowelI++;

     else if (arr[x] == 'o')
     vowelO++;

     else if (arr[x] == 'u')
     vowelU++;

     else if (arr[x] == 'y')
     vowelY++;

     else
     elsePlaceHolder++;

  }
  System.out.print(vowelA+" "+vowelE+" "+vowelI+" "+vowelO+" "+vowelU+" "+vowelY);
}

它会起作用。另外你还没有初始化那些元音迭代器，但你已经增加了它们！

Answer 2

您将创建一次数组并计算元素数。

char[] chars = createArray();

for(int i = 0; i < chars.length; i++){
    if(chars[i] == 'a')
        increment number of A's
    else if ...
}

而不是创建5个元素，我创建了一个大小为5且a为arr[0]的数组，e为arr[1]等。

在您的代码中

int[] arr = new int[5];
for(int i = 0; i < chars.length; i++){
    if(chars[i] == 'a')
        arr[0]++;
    else if(chars[i] == 'e')
        arr[1]++;
    //etc
}

Answer 3

嗨，我刚刚更改了你的代码。希望对你有所帮助。看看这个！

private static int vowelA=0;
private static int vowelE=0;
private static int vowelI=0; 
private static int vowelO=0;
private static int vowelU=0;
private static int vowelY=0;
private static int elsePlaceHolder = 0;

public static void main(String[] args) {

        char[] chs = createArray();
        System.out.println("vowelA : "+vowelA);
        System.out.println("vowelE : "+vowelE);
        System.out.println("vowelI : "+vowelI);
        System.out.println("vowelO : "+vowelO);
        System.out.println("vowelU : "+vowelU);
        System.out.println("vowelY : "+vowelY);
}

//method to generate random character between ch1 and ch2
   public static char getRandomCharacter(char ch1, char ch2)
   {

      return (char) (ch1 + Math.random() * (ch2 -ch1 +1));

   }

//==========================================   

   //method to assign generated characters (between a and z) to a 100 character array
   public static char[] createArray()
   {

      //declare a 100 character array
      char[] character = new char[100];

      //for loop assigning the random characters to the array using getRandomCharacter method
      for (int x = 0; x < character.length; x++){
      character[x] = getRandomCharacter('a', 'z');
      countArray(character[x]);
      }
      //for loop outputting the characters in the array
      for (int x = 0; x < character.length; x++)
      System.out.println(character[x]);

      return character;

   }

   public static void countArray(char ch)
   {

         if (ch == ('a')){
         vowelA++;}
         else if (ch == 'e'){
         vowelE++;}
         else if (ch == 'i'){
         vowelI++;}
         else if (ch == 'o'){
         vowelO++;}
         else if (ch == 'u'){
         vowelU++;}
         else if (ch == 'y'){
         vowelY++;}
         else{
         elsePlaceHolder++;}
   }

Answer 4

    char[] randomc = new char[]{'a','b','i','i','o','u','u','e','e','e','e','e','e','z','b','f'};
    int[] voweltable = new int[] {0, 0, 0, 0, 0, 0}; // Last element is for non-vowels
    for (int i = 0; i <= randomc.length - 1; i++)
    {
        switch(randomc[i])
        {
            case 'a':
                voweltable[0]++;
                break;
            case 'e':
                voweltable[1]++;
                break;
            case 'i':
                voweltable[2]++;
                break;
            case 'o':
                voweltable[3]++;
                break;
            case 'u':
                voweltable[4]++;
                break;
            default:
                voweltable[5]++;
                break;
        }
    }
    for (int i = 0; i <= voweltable.length -1; i++)
        System.out.println(voweltable[i]);

Answer 5

与getRandomCharacter()方法相同，您可以尝试使用字符的int值，并为ch1和{{之间的范围大小构建一个int数组。 1}}，然后增加每次出现的值，然后打印元音的计数，如：

ch2

如何创建计算数组中字符的方法

5 个答案: