Question

散景版：0.10 Python：3.4 木星：4.x

目标：创建一个仅显示从散点图中选择的数据的表

问题：DataTable仅在单击后自行刷新尽管如此：s2.trigger（＆＃39;更改＆＃39;）。在Bokeh网站上的其他例子之一 plot将使用此技术更新另一个：请参阅http://bokeh.pydata.org/en/latest/docs/user_guide/interaction.html#customjs-for-selections

如果您使用上述版本，下面的代码应该在Jupyter笔记本中运行。

并且，感谢您的帮助。乔

    from bokeh.io import output_notebook, show
    from bokeh.plotting import figure
    from bokeh.models import CustomJS, ColumnDataSource
    from bokeh.models.widgets import DataTable, TableColumn
    from bokeh.io import vform

    output_notebook()

    x = list(range(-20, 21))
    y0 = [abs(xx) for xx in x]

    # create a column data source for the plots to share
    source = ColumnDataSource(data=dict(x=x, y0=y0))
    s2 = ColumnDataSource(data=dict(x=[1],y0=[2]))

    source.callback = CustomJS(args=dict(s2=s2), code="""
            var inds = cb_obj.get('selected')['1d'].indices;
            var d1 = cb_obj.get('data');
            var d2 = s2.get('data');
            d2['x'] = []
            d2['y0'] = []
            for (i = 0; i < inds.length; i++) {
                d2['x'].push(d1['x'][inds[i]])
                d2['y0'].push(d1['y0'][inds[i]])
            }
            s2.trigger('change');
        """)


    # create DataTable

    columns = [
            TableColumn(field="x", title="x"),
            TableColumn(field="y0", title="y0"),
        ]
    dt = DataTable(source=s2, columns=columns, width=300, height=300 )

    # create a new plot and add a renderer
    TOOLS = "box_select,lasso_select,help"
    left = figure(tools=TOOLS, width=300, height=300)
    left.circle('x', 'y0', source=source)


    show(vform(left,dt))

Answer 1

只有CustomJS触发s2更改，因此dt不会发生变化是正常的。

这将完成工作，dt移到JS之上，dt在JS中传递，并且dt被触发：

dt = DataTable(source=s2, columns=columns, width=300, height=300 )
source.callback = CustomJS(args=dict(s2=s2, dt=dt), code="""
        var inds = cb_obj.get('selected')['1d'].indices;
        var d1 = cb_obj.get('data');
        var d2 = s2.get('data');
        d2['x'] = []
        d2['y0'] = []
        for (i = 0; i < inds.length; i++) {
            d2['x'].push(d1['x'][inds[i]])
            d2['y0'].push(d1['y0'][inds[i]])
        }
        console.log(dt);
        s2.trigger('change');
        dt.trigger('change');
    """)

Answer 2

如果您只关心更新表，那么您实际上不需要传递数据源和“数据表”。这是因为“数据表”已将源作为属性。这是完整的代码（请注意，只传递“dt”）：

from bokeh.io import output_notebook, show
from bokeh.plotting import figure
from bokeh.models import CustomJS, ColumnDataSource
from bokeh.models.widgets import DataTable, TableColumn
from bokeh.io import vform

output_notebook()

x = list(range(-20, 21))
y0 = [abs(xx) for xx in x]

# create a column data source for the plots to share
source = ColumnDataSource(data=dict(x=x, y0=y0))
s2 = ColumnDataSource(data=dict(x=[1],y0=[2]))

# create DataTable

columns = [
    TableColumn(field="x", title="x"),
    TableColumn(field="y0", title="y0"),
]
dt = DataTable(source=s2, columns=columns, width=300, height=300 )

# create a new plot and add a renderer
TOOLS = "box_select,lasso_select,help"
left = figure(tools=TOOLS, width=300, height=300)
left.circle('x', 'y0', source=source)

source.callback = CustomJS(args=dict(mytable=dt), code="""
var inds = cb_obj.get('selected')['1d'].indices;
var d1 = cb_obj.get('data');
var d2 = mytable.get('source').get('data');
d2['x'] = []
d2['y0'] = []
for (i = 0; i < inds.length; i++) {
d2['x'].push(d1['x'][inds[i]])
d2['y0'].push(d1['y0'][inds[i]])
}
mytable.trigger('change');
""")

show(vform(left,dt))

BoTV DataTable在触发后不会更新（＆＃39;更改＆＃39;）而不点击标题

2 个答案: