Question

我正在尝试从Django网站上的外部域捕获跟踪信息。外部域上的客户端加载了一个js片段：

(function() {
  var img = new Image,
      url = encodeURIComponent(document.location.href),
      title = encodeURIComponent(document.title),
      ref = encodeURIComponent(document.referrer);
  img.src = '%s/track.gif?url=' + url + '&t=' + title + '&ref=' + ref;
})();

这会在/track.gif上创建一个图像获取请求回到我的服务器。如何让我的TrackView将get请求视为POST请求并将参数输入我的数据库？

其他信息

urls.py

urlpatterns = patterns('',
    url(r'^browse_event$', BrowseEventView.as_view(), name='browse_event'),
    url(r'^cart_event$', CartEventView.as_view(), name='cart_event'),
    url(r'^product_view$', ProductView.as_view(), name='product_view'),
    url(r'^track.gif$', TrackView.as_view(), name='track_view'),
)

models.py

class Track(CommonDateTime, models.Model):
    domain = models.CharField(max_length=50)
    url_name = models.CharField(max_length=200)
    title = models.CharField(max_length=200)
    ip = models.CharField(max_length=200)
    referrer = models.CharField(max_length=200)

    class Meta:
        db_table = 'track_test'
        verbose_name = 'Tracking pixel test'
        verbose_name_plural = 'Tracking pixel tests'

forms.py

class TrackForm(forms.Form):
    domain = forms.CharField()
    url_name = forms.CharField()
    title = forms.CharField()
    ip = forms.CharField()
    referrer = forms.CharFeld()

views.py

class TrackView(FormView):
    form_class = TrackForm
    success_url = '/'

    def form_valid(self, form):
        try:
            track = Track.objects.get(domain = form.cleaned_data['domain'])
            track.url_name = form.cleaned_data['url']
            track.title = form.cleaned_data['title']
            track.ip = form.cleaned_data['ip']
            track.referrer = form.cleaned_data['referrer']
            track.save()
        except Track.DoesNotExist:
            track = Track(
                        domain = form.cleaned_data['domain']
                        url_name = form.cleaned_data['url']
                        title = form.cleaned_data['title']
                        ip = form.cleaned_data['ip']
                        referrer = form.cleaned_data['referrer']
                      )
            track.save()
        return super(TrackView, self).form_valid(form)

Answer 1

为什么需要POST请求？只需使用简单的get（） - 类函数视图实现GET请求。

您可以直接使用check query request.GET，或者如果您想使用表单，您可以使用request.GET作为参数来实例化它，但是恕我直言，没有真正的原因。

你可以这样做：

class TrackView(View):
    def get(self, request):
        try:
            track,_ = Track.objects.get_or_create(domain = request.GET['domain'])
            track.url_name = request.GET['url']
            track.title = request.GET['title']
            track.ip = request.GET['ip']
            track.referrer = request.GET['referrer']
            track.save()
            return HttpResponse(status=200) 
        except KeyError:
            return HttpResponse(status=400)

如何在django中的GET请求中存储URL参数？

1 个答案: