如何将字符串类型的字段包含在聚合的结果集中? 例如,给出以下映射:
skip=0
示例数据:
{
"sport": {
"mappings": {
"runners": {
"properties": {
"name": {
"type": "string"
},
"city": {
"type": "string"
},
"region": {
"type": "string"
},
"sport": {
"type": "string"
}
}
}
}
}
}
如何将字段curl -XPOST "http://localhost:9200/sport/_bulk" -d'
{"index":{"_index":"sport","_type":"runner"}}
{"name":"Gary", "city":"New York","region":"A","sport":"Soccer"}
{"index":{"_index":"sport","_type":"runner"}}
{"name":"Bob", "city":"New York","region":"A","sport":"Tennis"}
{"index":{"_index":"sport","_type":"runner"}}
{"name":"Mike", "city":"Atlanta","region":"B","sport":"Soccer"}
'
包含在聚合的结果集中:
name
答案 0 :(得分:0)
如果我理解正确的话,这似乎就是你想要的:
POST /sport/_search
{
"size": 0,
"aggregations": {
"city_terms": {
"terms": {
"field": "city"
},
"aggs": {
"name_terms": {
"terms": {
"field": "name"
}
}
}
}
}
}
根据您提供的数据,它会返回:
{
"took": 43,
"timed_out": false,
"_shards": {
"total": 5,
"successful": 5,
"failed": 0
},
"hits": {
"total": 3,
"max_score": 0,
"hits": []
},
"aggregations": {
"city_terms": {
"doc_count_error_upper_bound": 0,
"sum_other_doc_count": 0,
"buckets": [
{
"key": "new",
"doc_count": 2,
"name_terms": {
"doc_count_error_upper_bound": 0,
"sum_other_doc_count": 0,
"buckets": [
{
"key": "bob",
"doc_count": 1
},
{
"key": "gary",
"doc_count": 1
}
]
}
},
{
"key": "york",
"doc_count": 2,
"name_terms": {
"doc_count_error_upper_bound": 0,
"sum_other_doc_count": 0,
"buckets": [
{
"key": "bob",
"doc_count": 1
},
{
"key": "gary",
"doc_count": 1
}
]
}
},
{
"key": "atlanta",
"doc_count": 1,
"name_terms": {
"doc_count_error_upper_bound": 0,
"sum_other_doc_count": 0,
"buckets": [
{
"key": "mike",
"doc_count": 1
}
]
}
}
]
}
}
}
(如果这些结果不符合您的预期,您可能需要将"index":"not_analyzed"
添加到地图中的一个或两个字段。)
以下是我用来测试它的代码:
http://sense.qbox.io/gist/07735aadc082c1c60409931c279f3fd85a340dbb