Question

如何将unix时间戳1280214000转换为人类可读日期？

Answer 1

您也可以使用日期功能

http://us.php.net/manual/en/function.date.php

<?php
// Assuming today is March 10th, 2001, 5:16:18 pm, and that we are in the
// Mountain Standard Time (MST) Time Zone

$today = date("F j, Y, g:i a");                 // March 10, 2001, 5:16 pm
$today = date("m.d.y");                         // 03.10.01
$today = date("j, n, Y");                       // 10, 3, 2001
$today = date("Ymd");                           // 20010310
$today = date('h-i-s, j-m-y, it is w Day');     // 05-16-18, 10-03-01, 1631 1618 6 Satpm01
$today = date('\i\t \i\s \t\h\e jS \d\a\y.');   // it is the 10th day.
$today = date("D M j G:i:s T Y");               // Sat Mar 10 17:16:18 MST 2001
$today = date('H:m:s \m \i\s\ \m\o\n\t\h');     // 17:03:18 m is month
$today = date("H:i:s");                         // 17:16:18
?>

只需将你的unix时间戳作为第二个参数传递。

Answer 2

您可以使用strftime。 E.g：

strftime("%x", 1280214000);

有关所有格式选项，请参阅文档。

Answer 3

您可以使用date：

date('Y-m-d H:i:s', $timestamp);

Answer 4

//Monday 8th of August 2005 03:12:46 PM
echo(date("l jS \of F Y h:i:s A", "1280214000"));

Answer 5

您可以使用date功能。

http://php.net/manual/en/function.date.php

将unix时间戳转换为日期

5 个答案: