I am trying to use ajax to change the content of a div (as html), when a link is clicked in that same div. I am not very skilled in ajax, so I am pretty sure that this is a noob question. I have tried searching the web for solutions, but I didn't manage to make anything work.
I have a div with the id "main" and inside it I am trying to make a link with the id "link01". When "link01" is clicked, I want "main" to load content from another div in another page ("txt2"-div in site2.html). But I can't get it to work.
Firstly, this is my index.html page:
<head>
<title>site1</title>
<meta charset="UTF-8">
</head>
<body>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.5/jquery.min.js"></script>
<script type="text/javascript" language="javascript">
$(document).ready(function() {
$('#link01').click(function() {
$('#main').load('site2.html #txt2', function() {});
});
});
</script>
<div id="main">
<a>
<div id="link01">link</div>
</a>
Main div where the content will change</div>
<br>
<br>
</body>
</html>
And this is my site2.html page:
<!DOCTYPE html>
<html>
<head>
<title>Site2</title>
<meta charset="UTF-8">
</head>
<body>
<div id="txt2">Text that will go into the main div at the index-page when link01 is clicked (contains links, images, etc)</div>
</body>
</html>
I have probably misunderstood something completeley.
答案 0 :(得分:0)
There is a very bad practice way that may work... But you should really have a server side code that listens you your ajax call, and returns just the desired HTML fragment as a response. Having said that, try this, it MIGHT work (didn't check):
$(function() {
$('#link01').click(function(){
$.ajax({
url: 'site2.html',
type: 'GET',
success: function(data){
data = $(data);
var $div = $('#txt2', data);
$('#main').html($div);
}
});
});
});