Question

Here is some sample xml:

<Transaction>
<Tender>
    <TenderIdentifierSourceCode LanguageCode="eng" CodeContent="06"/>
</Tender>

I want to iterate through a directory and move all the xml files that contain the attribute CodeContent where the value is '06':

Tender/TenderIdentifierSourceCode/@CodeContent = '06'

So far, I have this which generates a file list (and just checks to see if the node exists) - But this doesn't work. And I want to check the VALUE of the attribute CodeContent rather than element existance:

$Path = "C:\Users\Bex\Documents\Client Projects\QA Refresh\Useful Powershell Scripts"
$PathArray = @()
$Results = "D:\MatchingStringResults.txt"

Get-ChildItem $Path -Filter "*.xml" -Recurse | 
   Where-Object { $_.Attributes -ne "Directory"} | 
ForEach-Object { $NodeExists = $xml.Transaction.Tender.TenderIdentifierSourceCode
  if($NodeExists){ $PathArray += $_.FullName
  }
  }
Write-Host "Contents of ArrayPath:" $PathArray | ForEach-Object {$_}
read-host "Script Complete - Press ENTER to exit"
$PathArray | % {$_} | Out-File $Results

Answer 1

这样可行。它找到带有字符串的文件并移动到新目录。但是，正如PetSerAl提供的答案一样，我想检查特定的xml路径，因为CodeContent属性存在于多个元素中。

$Path = "C:\Users\Bex\Documents\Client Projects\QA Refresh\Useful Powershell    Scripts\Apple Pay Transactions"
$Text = 'CodeContent="06"'
$PathArray = @()
$Results = "D:\MatchingStringResults.txt"
$Destination = "C:\Users\Bex\Documents\Client Projects\QA Refresh\Useful     Powershell Scripts\FileList"

# This code snippet gets all the files in $Path that end in ".xml" and any subdirectories.
Get-ChildItem $Path -Filter "*.xml" -Recurse | 
   Where-Object { $_.Attributes -ne "Directory"} | 
      ForEach-Object { 
         If (Get-Content $_.FullName | Select-String -Pattern $Text) {
            $PathArray += $_.FullName
            Move-Item -path $_.FullName -destination $Destination
         }
      }

Get a list of files that contain an xml attribute with a certain value

1 个答案: