Question

我希望QString允许这样做：

QString myString("School is LameCoolLame and LameRadLame");
myString.replace(QRegularExpression("Lame(.+?)Lame"),"\1");

离开

"School is Cool and Rad"

与我在文档中看到的不同，执行此操作需要您做的更复杂（来自文档）：

QRegularExpression re("\\d\\d \\w+");
QRegularExpressionMatch match = re.match("abc123 def");
if (match.hasMatch()) {
    QString matched = match.captured(0); // matched == "23 def"
    // ...
}

或者就我而言：

QString myString("School is LameCoolLame and LameRadLame");
QRegularExpression re("Lame(.+?)Lame");
QRegularExpressionMatch match = re.match(myString);
if (match.hasMatch()) {
    for (int i = 0; i < myString.count(re); i++) {
        QString newString(match.captured(i));
        myString.replace(myString.indexOf(re),re.pattern().size, match.captured(i));
    }
}

这似乎没有效果，（我实际上放弃了）。必须有一种更方便的方式。为了简单起见和代码可读性，我想知道采用最少行代码来完成此任务的方法。

感谢。

Answer 1

QString myString("School is LameCoolLame and LameRadLame");
myString.replace(QRegularExpression("Lame(.+?)Lame"),"\\1");

Above code works as you expected. In your version, you forgot to escape the escape character itself.

在Qt中，用最少量的代码替换正则表达式捕获的字符串匹配是什么？

1 个答案: