Question

我有一个下拉菜单，其中包含一些类别，每个类别都有自己的子类别，我想向他们展示购买选择类别名称但它不起作用，我是否错过了某些东西，或者我完全错了？

Sub CopyValue()
 Dim wbFrom As Workbook, wbto As Workbook
 Dim wsFrom As Worksheet, wsTo As Worksheet

 Set wbFrom = Workbooks(fromimportfilename)
 Set wbto = Workbooks(toimportfilename)
 Set wsFrom = wbFrom.Sheets("Sheet1")
 Set wsTo = wbto.Sheets("Sheet1")

'to copy all cells, visible and Hidden
wsTo.Range("E9:E200").Value = wbFrom.Range("F9:F200").Value

'to copy only the visible cells
Set rngVisible = wbFrom.Range("F9:F200").SpecialCells(xlCellTypeVisible)
rngVisible.Copy Destination:=wsTo.Range("F9") 'I use F colum to show u the difference from the two paste method

End Sub

Answer 1

试试这个，

if table is not empty
            do something
else 
            do something else
end if

在$.ajax({ type:"POST", url:"get_subcategory.php", data:data, success: function(data){ alert(data)// this will have the second dropdown. add to desired place in your view. } });

get_subcategory.php

Answer 2

<强> SomePage.php

<form id="form" name="form">
    <div id='category'>
        <label for="category" id="error">Empty</label>
        <select name="category" id="category">
            <option></option>
            <option value="News">News</option>
            <option value="Items">Items</option>
            <option value="Updates">Updates</option>
        </select>
    </div>
    <div id='subcategory'>
    </div>
</form>


<script>
    $('#category').change(function(){
        var CatName= $('#category').val();
        $.ajax({url:"AjaxSelectCategory.php?CatName="+CatName,cache:false,success:function(result){
            $('#subcategory').html(result);
        }});
    });
</script>

创建新页 AjaxSelectCategory.php [注意：如果要更改此页面名称。也可以更改<script></script>标记。两者都是相关的。]

<?php
include("connect.php");
if(!empty($_GET['CatName']))
{
    $sql=$con->prepare("SELECT * FROM categorys WHERE category=:category ");
    $sql->bindparam(":category",$_GET['CatName']);
    $sql->execute();
    ?>
    <select name='subcategory'>
    <?php
    while($r=$sql->fetch())
    {?>
        <option value="<?php echo $r['subcategory'];?>"><?php echo $r['subcategory'];?></option>
    </select>
    <?php }
}?>

使用ajax和php选择行表

2 个答案: