我想在页面加载时修复谷歌地图的缩放。然后我需要放大/缩小它。我把代码放在下面。
缩放设置为6.但加载网页时始终进行最大缩放。加载地图时无法将缩放固定为6.
<script type="text/javascript">
var icon = new google.maps.MarkerImage("http://maps.google.com/mapfiles/ms/micons/blue.png",
new google.maps.Size(32, 32), new google.maps.Point(0, 0),
new google.maps.Point(16, 32));
var center = null;
var map = null;
var currentPopup;
var bounds = new google.maps.LatLngBounds();
function addMarker(lat, lng, info) {
var pt = new google.maps.LatLng(lat, lng);
bounds.extend(pt);
var marker = new google.maps.Marker({
position: pt,
icon: icon,
map: map
});
var popup = new google.maps.InfoWindow({
content: info,
maxWidth: 300
});
google.maps.event.addListener(marker, "click", function() {
if (currentPopup != null) {
currentPopup.close();
currentPopup = null;
}
popup.open(map, marker);
currentPopup = popup;
});
google.maps.event.addListener(popup, "closeclick", function() {
map.panTo(center);
currentPopup = null;
});
}
function initMap() {
map = new google.maps.Map(document.getElementById("map"), {
center: new google.maps.LatLng(0, 0),
zoom: 6,
mapTypeId: google.maps.MapTypeId.ROADMAP,
mapTypeControl: true,
mapTypeControlOptions: {
style: google.maps.MapTypeControlStyle.HORIZONTAL_BAR
},
navigationControl: true,
navigationControlOptions: {
style: google.maps.NavigationControlStyle.SMALL
}
});
<?
$lat='1.281776';
$lon='103.844945';
$name= $lat;
$desc= $lon;
echo ("addMarker($lat, $lon,'<b>$name</b><br/>$desc');\n");
?>
center = bounds.getCenter();
map.fitBounds(bounds);
}
</script>
答案 0 :(得分:3)
您的地图因
而缩小 center = bounds.getCenter();
map.fitBounds(bounds);
它尝试拟合边界以包含您添加的点,而中心保持在初始化设置的0,0。
而是使用setCenter
之类的
center = bounds.getCenter();
map.setCenter(center);