Question

我遇到了一个奇怪的问题。在我的UI-textview中我详细说明了文字，我想突出显示/用特定单词开头的某一行或颜色。到目前为止，我能够找到起始单词的位置但不是能够找到该行和段落的结尾。问题是新行（\ n）无法识别，因为我已经尝试过了。

任何人都可以帮我找到解决方案。这是代码

NSArray *matches = [regex matchesInString:self.textfiled.text options:0 range:NSMakeRange(0, self.textfiled.text.length)];
        for (NSTextCheckingResult *match in matches) {
            NSString *string =self.textfiled.text;
            NSRange wordRange = [match rangeAtIndex:0];
            unsigned long  lock=0;
            unsigned long i=0;
             [stirng replaceCharactersInRange:wordRange withString:@"\nདཔེར་ན། "];
            unsigned long length = [string length];
            unsigned long  paraStart = wordRange.length,paraEnd =0,contentsEnd =0;
            NSMutableArray *array = [NSMutableArray array];
            NSRange currentRange;

            for( i=0;![[self.textfiled.text substringWithRange:NSMakeRange(wordRange.location+i+1,1)] isEqualToString:@" "];i++)
            {

                NSLog(@"\n %lu------------>",i);
                lock=i;

              }


            NSLog(@"\n %lu------------>",lock);

          NSRange range = NSMakeRange(wordRange.location,wordRange.length);
           NSString *str = [self.textfiled.text substringWithRange:range];
             NSLog(@"\n%lu--------",[str length]);
            NSRange wordRanged1 = NSMakeRange(wordRange.location, 7+7);
            [stirng addAttribute:NSForegroundColorAttributeName value:[UIColor colorWithRed:22/255.0f green:123/225.0f blue:108/255.0f alpha:1.0f] range:wordRanged1];
}

Answer 1

根据您的代码的灵感，我创建了一个类似的解决方案，在给定匹配单词的起始字符的情况下，找到行结束和段落结束。段落以\n\n分隔，行以\n结尾。文本字段的结尾可能需要作为特殊情况处理。

请注意，.*将与给定正则表达式选项的行尾匹配。通过找到匹配的\n\n来找到段落结尾。

self.myText = @"hello world\n\nthis is a test\nsingle line\n\n";

NSError *error = NULL;
NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:@"hello.*"
                                                                       options:NSRegularExpressionCaseInsensitive
                                                                         error:&error];

NSArray *matches = [regex matchesInString:self.myText options:0 range:NSMakeRange(0, self.myText.length)];

for (NSTextCheckingResult *match in matches) {

    NSRange lineRange = [match rangeAtIndex:0];

    NSLog(@"match start is %lu", lineRange.location);

    NSLog(@"line end is %lu", lineRange.location + lineRange.length);

    // Find paragraph ends:
    NSInteger i = lineRange.location;
    unichar lineSeparator = 0x2028;

    while (i < self.myText.length - 1) {
        // Case where string uses \n\n to denote a paragraph:
        NSString *subString = [self.myText substringWithRange:NSMakeRange(i, 2)];
        if ( [subString isEqualToString:@"\n\n"] ) {
            NSLog(@"found paragraph end at %ld", (long)i);
        }

        // Case where text view uses line separator characters:
        if ([subString characterAtIndex:0] == lineSeparator && [subString characterAtIndex:1] == lineSeparator) {
            NSLog(@"found paragraph end at %ld", (long)i);
        }

        i++;           
    }
}

在我的样本中，我得到了

match start is 0
line end is 11
found paragraph end at 11
found paragraph end at 39

我已经创建了一个可视化结果的小指南：

hello world++this is a test+single line++
01234567891111111111222222222233333333334
          0123456789012345678901234567890

这可以适应一个独立的功能，应该提供你正在寻找的那种结果。

如何在知道字符串的起始位置时查找字符串的结尾

1 个答案: