Question

我正在寻找创建Java Server以处理客户端请求并对其进行响应的概念，我想使用不允许Socket连接的Google App引擎，因此客户端＆amp;在这种情况下服务器将使用Http请求进行通信？如果有人能向我澄清逻辑并提供几行代码，我会很高兴。

谢谢

Answer 1

The Simple Framework可能会提供您正在寻找的内容。它允许您以相对较小的开销将HTTP服务器嵌入到您的应用程序中：

import org.simpleframework.http.core.Container;
import org.simpleframework.transport.connect.Connection;
import org.simpleframework.transport.connect.SocketConnection;
import org.simpleframework.http.Response;
import org.simpleframework.http.Request;
import java.net.InetSocketAddress;
import java.net.SocketAddress;
import java.io.PrintStream;

public class HelloWorld implements Container {

   public void handle(Request request, Response response) {
      PrintStream body = response.getPrintStream();
      long time = System.currentTimeMillis();

      response.set("Content-Type", "text/plain");
      response.set("Server", "HelloWorld/1.0 (Simple 4.0)");
      response.setDate("Date", time);
      response.setDate("Last-Modified", time);

      body.println("Hello World");
      body.close();
   } 

   public static void main(String[] list) throws Exception {
      Container container = new HelloWorld();
      Connection connection = new SocketConnection(container);
      SocketAddress address = new InetSocketAddress(8080);

      connection.connect(address);
   }
}

要与其他解决方案进行比较，请注意Simple不仅可嵌入，而且是开源的，完全独立的和异步的。祝你好运！

Answer 2

感谢所有答案，但我需要一个简单的方法在Android App中使用它，如下面的代码：

HTTP GET

`

try {
        HttpClient client = new DefaultHttpClient();  
        String getURL = "http://www.google.com";
        HttpGet get = new HttpGet(getURL);
        HttpResponse responseGet = client.execute(get);  
        HttpEntity resEntityGet = responseGet.getEntity();  
        if (resEntityGet != null) {  
                    //do something with the response
                    Log.i("GET RESPONSE",EntityUtils.toString(resEntityGet));
                }
} catch (Exception e) {
    e.printStackTrace();
}`

HTTP POST

try {
    HttpClient client = new DefaultHttpClient();  
    String postURL = "http://somepostaddress.com";
    HttpPost post = new HttpPost(postURL); 
        List<NameValuePair> params = new ArrayList<NameValuePair>();
        params.add(new BasicNameValuePair("user", "kris"));
        params.add(new BasicNameValuePair("pass", "xyz"));
        UrlEncodedFormEntity ent = new UrlEncodedFormEntity(params,HTTP.UTF_8);
        post.setEntity(ent);
        HttpResponse responsePOST = client.execute(post);  
        HttpEntity resEntity = responsePOST.getEntity();  
        if (resEntity != null) {    
            Log.i("RESPONSE",EntityUtils.toString(resEntity));
        }
} catch (Exception e) {
    e.printStackTrace();
}

代码来自this site，您不需要任何其他Jar文件即可在Android中使用它，我可以将其与Google App引擎一起使用。

Java服务器处理客户端请求并响应它？

2 个答案: