我意识到这个问题已被问过一百万次了,并且有很多关于它的文档。但是,我无法以正确的格式输出结果。
以下代码来自:Replacing empty csv column values with a zero
DataTemplate
目前,要获得正确的输出.csv文件[即以正确的格式]可以在bash中运行以下命令:
# Save below script as RepEmptyCells.py
# Add #!/usr/bin/python to script
# Make executable by chmod +x prior to running the script on desired .csv file
# Below code will look through your .csv file and replace empty spaces with 0s
# This can be particularly useful for genetic distance matrices
import csv
import sys
reader = csv.reader(open(sys.argv[1], "rb"))
for row in reader:
for i, x in enumerate(row):
if len(x)< 1:
x = row[i] = 0
print(','.join(int(x) for x in row))
我尝试使用 #After making the script executable
./RepEmptyCells.py input.csv > output.csv # this produces the correct output
函数生成格式正确的csv.writer
文件(类似于output.csv
)而没有太多运气。
我想学习如何将最后一部分添加到代码中以自动执行该过程,而无需在bash中执行此操作。
我尝试过:
./RepEmptyCells.py input.csv > output.csv
当查看此代码和之前的原始文件时,它们看起来是一样的。
但是,当我在excel或iNumbers中打开它们时,后者(即f = open(output2.csv, 'w')
import csv
import sys
reader = csv.reader(open(sys.argv[1], "rb"))
for row in reader:
for i, x in enumerate(row):
if len(x)< 1:
x = row[i] = 0
f.write(','.join(int(x) for x in row))
f.close()
)只显示一行数据。
重要的是,output2.csv
和output.csv
都可以在Excel中打开。
答案 0 :(得分:3)
2个选项:
在您当前的f.write('\n')
声明后进行f.write
。
使用csv.writer
。你提到它但它不在你的代码中。
writer = csv.writer(f)
...
writer.writerow([int(x) for x in row]) # Note difference in parameter format
答案 1 :(得分:1)
一个不起眼的命题
#!/usr/bin/env python
# -*- coding: utf-8 -*-
import csv
import sys
# Use with statement to properly close files
# Use newline='' which is the right option for Python 3.x
with open(sys.argv[1], 'r', newline='') as fin, open(sys.argv[2], 'w', newline='') as fout:
reader = csv.reader(fin)
# You may need to redefine the dialect for some version of Excel that
# split cells on semicolons (for _Comma_ Separated Values, yes...)
writer = csv.writer(fout, dialect="excel")
for row in reader:
# Write as reading, let the OS do the caching alone
# Process the data as it comes in a generator, checking all cells
# in a row. If cell is empty, the or will return "0"
# Keep strings all the time: if it's not an int it would fail
# Converting to int will force the writer to convert it back to str
# anwway, and Excel doesn't make any difference when loading.
writer.writerow( cell or "0" for cell in row )
示例in.csv
1,2,3,,4,5,6,
7,,8,,9,,10
输出out.csv
1,2,3,0,4,5,6,0
7,0,8,0,9,0,10
答案 2 :(得分:0)
import csv
import sys
with open(sys.argv[1], 'rb') as f:
reader = csv.reader(f)
for row in reader:
print row.replace(' ', '0')
并且我不了解您使用shell和重定向的需要。 一个csv作家只是:
with open('output.csv', 'wb') as f:
writer = csv.writer(f)
writer.writerows(rows)