Question

我尝试使用spark（任何风格：pyspark，spark，spark sql等来计算复合兴趣（种类）。

我的数据形式如下：

+------------+------+------+--------+
| population | rate | year | city   |
+------------+------+------+--------+
| 100        | 0.1  | 1    | one    |
+------------+------+------+--------+
| 100        | 0.11 | 2    | one    |
+------------+------+------+--------+
| 100        | 0.12 | 3    | one    |
+------------+------+------+--------+
| 200        | 0.1  | 1    | two    |
+------------+------+------+--------+
| 1000       | 0.21 | 2    | three  |
+------------+------+------+--------+
| 1000       | 0.22 | 3    | three  |
+------------+------+------+--------+

population列错误（它来自两个表之间的join，未显示。）

我想使用前一行population的结果更新population*(1 + rate)列。我知道在sql我可以使用recursive CTE，但hiveql不支持。

你能给我一些建议吗？

Answer 1

据我所知，你所需要的只是一些基本的代数和窗函数。首先让我们重新创建示例数据：

import pandas as pd  # Just to make a reproducible example

pdf = pd.DataFrame({
    'city': {0: 'one', 1: 'one', 2: 'one', 3: 'two', 4: 'three', 5: 'three'},
    'population': {0: 100, 1: 100, 2: 100, 3: 200, 4: 1000, 5: 1000},
    'rate': {0: 0.10000000000000001,
     1: 0.11,
     2: 0.12,
     3: 0.10000000000000001,
     4: 0.20999999999999999,
     5: 0.22},
    'year': {0: 1, 1: 2, 2: 3, 3: 1, 4: 2, 5: 3}})

df = sqlContext.createDataFrame(pdf)

df.show()
## +-----+----------+----+----+
## | city|population|rate|year|
## +-----+----------+----+----+
## |  one|       100| 0.1|   1|
## |  one|       100|0.11|   2|
## |  one|       100|0.12|   3|
## |  two|       200| 0.1|   1|
## |three|      1000|0.21|   2|
## |three|      1000|0.22|   3|
## +-----+----------+----+----+

接下来我们定义窗口：

import sys
from pyspark.sql.window import Window
from pyspark.sql.functions import exp, log, sum, first, col, coalesce

# Base window
w = Window.partitionBy("city").orderBy("year")

# ROWS BETWEEN UNBOUNDED PRECEDING AND 1 PRECEDING
wr = w.rowsBetween(-sys.maxsize, -1)

和一些专栏：

# Take a sum of logarithms of rates over the window
log_sum = sum(log(col("rate") + 1)).over(wr)

# Take sum of logs and exponentiate to go back to original space 
cumulative_rate = exp(log_sum).alias("cumulative_rate")

# Find base population for each group
base_population = first("population").over(w).alias("base_population")

# Prepare final column (base population * cumulative product of rates)
current_population = coalesce(
     # This is null for the first observation in a group
     cumulative_rate * base_population, 
     # so we provide population as an alternative
     col("population")  
).alias("current_population")

最后我们可以使用以下这些

df.select("*", current_population).show()

## +-----+----------+----+----+------------------+
## | city|population|rate|year|current_population|
## +-----+----------+----+----+------------------+
## |three|      1000|0.21|   2|            1000.0|
## |three|      1000|0.22|   3|            1210.0|
## |  two|       200| 0.1|   1|             200.0|
## |  one|       100| 0.1|   1|             100.0|
## |  one|       100|0.11|   2|110.00000000000001|
## |  one|       100|0.12|   3|122.10000000000004|
## +-----+----------+----+----+------------------+

如何使用Spark数据框中前一行的两列计算行中的列？

1 个答案: