Question

您好我有简单的Angular和JAX RS应用程序。我的班级：

public class User {

    private String firstName;
    private String lastName;

    public User(String firstName, String lastName) {
        this.firstName = firstName;
        this.lastName = lastName;
    }

    public String getFirstName() {
        return firstName;
    }

    public void setFirstName(String firstName) {
        this.firstName = firstName;
    }

    public String getLastName() {
        return lastName;
    }

    public void setLastName(String lastName) {
        this.lastName = lastName;
    }

}

文件AngularCtrl.js是Angular控制器：

    (function () {
    var app = angular.module('app', []);
    var serviceURI = "/Airlines/rest/";
    app.controller('flightCtrl', ['$scope', '$http', function ($scope, $http) {
            $scope.value;
            getAllUsers($scope, $http);
        }]);
    function getAllUsers($scope, $http) {
        $http.get(serviceURI + "flights").success(function (data) {
            $scope.value = data;
        }).error(function (error) {
            alert("Some Error Occurred!");
        });
    }

})();

休息班：

@RequestScoped
@Path("/flights")
public class FlightRest {

    @GET
    @Produces(MediaType.APPLICATION_JSON)
    public User listAll() {
        User user = new User("John", "Thompson");
        System.out.println("Before return");
        return user;
    }

}

和简单的观点：

<html>
<head>
    <title>Arilines</title>
    <meta charset="UTF-8">
    <link rel="stylesheet" href="css/bootstrap.min.css">
    <link rel="stylesheet" href="css/main.css">
    <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.3/jquery.min.js"></script>
    <script src="http://maxcdn.bootstrapcdn.com/bootstrap/3.3.5/js/bootstrap.min.js"></script>
</head>
<body>
    <div data-ng-app="app">
        <div  data-ng-controller="flightCtrl">
            {{value.firstName}} {{value.lastName}}
        </div>
    </div>
    <script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.4.7/angular.min.js"></script>
    <script src="js/AngularCtrl.js"></script>
</body>

当我开始申请时，我会收到提醒：

警告（＆＃34;发生了一些错误！＆＃34;）;

我班上有什么不对，而不是成功错误？为什么不获取JSON数据？我确定我的请求到达了JAX-RS类，因为在控制台中我看到来自类的消息

System.out.println（＆＃34;返回之前＆＃34;）;

Answer 1

您的JAX-RS类没有问题。它按预期返回一个json。我执行了代码，它在浏览器上正确显示了用户名。

我必须做的唯一调整是从JAX-RS向我的响应添加标头以允许跨域访问（CORS），因为我在另一个端口上托管了REST服务。这是我做的调整： -

@GET
@Produces(MediaType.APPLICATION_JSON)
public Response listAll() {
    User user = new User("John", "Thompson");
    System.out.println("Before return");
    return Response.status(Status.OK)
    .header("Access-Control-Allow-Origin", "*")
    .header("Access-Control-Allow-Headers", "origin, content-type, accept, authorization")
    .entity(user)
    .type(MediaType.APPLICATION_JSON).build();
}

JAX-RS方法不返回来自对象

1 个答案: