所以我正在尝试编写一个很好的战争游戏,当我尝试将一个对象(一张牌)从一个列表(手)移动到另一个列表时,我遇到了错误。还有其他一些关于此事的帖子,但我无法拼凑出怎么做...... 这是代码:
import random
cardvalues = {"ace" : 13 , "2" : 2 , "3" : 3 , "4" : 4 , "5" : 5 , "6" : 6, "7" : 7 , "8" : 8 , "9" : 9, "10" : 10 , "jack" : 11 , "queen" : 12 , "king" : 13}
suits = {"clubs" : 1, "diamonds" : 2 , "spades" : 3 , "hearts" : 4}
deck = []
currentDeck = []
class card:
def __init__ (self, value, suit):
if value not in cardvalues:
raise RuntimeError("must input valid card value")...
### [此处的代码已被删除,因为它不会导致问题]
def battle():
if hand1[0] >= hand2[0]:
hand1.append[hand2.pop(0)] #The error happens in this function in the .append
print("player 1 won the battle")
elif hand1[0] < hand2[0]:
hand2.append[hand1.pop(0)]
print("player 2 won the battle")
else:
raise RuntimeError("something wrong")
while len(hand1) > 0:
while len(hand2) > 0:
battle()
if len(hand1) == 0:
print("PLAYER 2 WON THE WAR")
elif len(hand2) == 0:
print("PLAYER 1 WON THE WAR")
else:
print("no one won?")
谢谢!
我不仅需要帮助找到我的错误,但这是什么意思?
答案 0 :(得分:23)
您在尝试拨打0 <= n < s.size()
时使用function keyword_replace($where) {
$keywords_to_replace = get_option('keywords_to_replace');
$keyword_links = get_option('keyword_links');
$KWs = explode("\n", $keywords_to_replace);
$URLs = explode("\n", $keyword_links);
$pattern = array();
$replacement = array();
for($i=0; $i< count($KWs); $i++) {
$pattern2 = '/<a[^>]*>(.*?)'.$KWs[$i].'(.*?)</a>/';
if(preg_match($pattern2, $where)) {
continue;
} else {
$pattern[$i] = '\'(?!((<.*?)|(<a.*?)))(\b'. $KWs[$i] . '\b)(?!(([^<>]*?)>)|([^>]*?</a>))\'si';
$replacement[$i] .= '<a href="'.$URLs[$i].'" target="_blank">'.$KWs[$i].'</a>';
}
}
return preg_replace($pattern, $replacement, $where, -1);
}
add_filter('the_content','keyword_replace');
代替[]
。