Question

过去一周左右我一直在研究这个问题，我似乎无法提出解决方案。我正在尝试创建一个查询，我从各种表中获取数据，主要是我在几周（每周）汇总日期。因此，我创建了一个日历表，如下所示;

   DATE,    YEAR, MONTH_OF_YEAR, WEEK_OF_YEAR,

2014-01-01  2014       1               1
2014-01-02  2014       1               1
2014-01-03  2014       1               1
2014-01-04  2014       1               1
2014-01-05  2014       1               1
2014-01-06  2014       1               2

数据一直持续到。

所以，我已经汇总了所有这些表格和数据，并希望过去10周的结果以及没有活动的几周我想要0。

我写了这个查询来从2个表中获取数据并在日历表的week_of_year上加入它们（请不要把我钉在十字架上，SQL不是我的第一语言。）

select calendar.YEAR,
       calendar.WEEK_OF_YEAR,
       ifnull(count(data_transfer.id_data_transfer), 0) as DEVICE_TO_DEVICE,
       ifnull(count(device.tag_code), 0) as DEVICE_REGISTRATION
from calendar
left join data_transfer 
    on data_transfer.WEEK_NUMBER=calendar.WEEK_OF_YEAR -- wee number
        and data_transfer.year = calendar.YEAR -- need the year of week
        and data_transfer.id_customer = 1 --  specific customer
        and data_transfer.cloud_type is null --  specific type etc
        and date(data_transfer.TRANSFER_START_TIME) > date(date_sub(now(), INTERVAL 1 YEAR)) -- for the final week to be this week
left join device 
    on device.WEEK_NUMBER = calendar.WEEK_OF_YEAR       
        and device.year = calendar.YEAR
        and device.ID_CUSTOMER = 1
        and date(device.DEVICE_CREATE_DATE) > date(date_sub(now(), INTERVAL 1 YEAR)) -- for the final week to be this week
where date(calendar.date) > date(date_sub(now(),INTERVAL 1 YEAR)) -- for the final week to be this week
group by calendar.year, calendar.WEEK_OF_YEAR
order by calendar.year, calendar.WEEK_OF_YEAR;

查询返回多个双打，我想这可能是由于日期表中有多个为week_of_year的条目，即由于一周中的天数而导致的数据？

例如，当我使用group_concat（specific_field）运行它时，我得到的结果如图所示。这是我试图解释的问题

YEAR, WEEK_OF_YEAR, DEVICE_TO_DEVICE, DEVICE_REGISTRATION, group_concat(data_transfer.id_data_transfer), id
2014    46  280 280 50,50,50,50,50,50,50,50,50,50,50,50,50,50,50,50,50,50,50,50,50,50,50,50,50,50,50,50,50,50,50,50,50,50,50,51,51,51,51,51,51,51,51,51,51,51,51,51,51,51,51,51,51,51,51,51,51,51,51,51,51,51,51,51,51,51,51,51,51,51,52,52,52,52,52,52,52,52,52,52,52,52,52,52,52,52,52,52,52,52,52,52,52,52,52,52,52,52,52,52,52,52,52,52,52,53,53,53,53,53,53,53,53,53,53,53,53,53,53,53,53,53,53,53,53,53,53,53,53,53,53,53,53,53,53,53,53,53,53,53,54,54,54,54,54,54,54,54,54,54,54,54,54,54,54,54,54,54,54,54,54,54,54,54,54,54,54,54,54,54,54,54,54,54,54,55,55,55,55,55,55,55,55,55,55,55,55,55,55,55,55,55,55,55,55,55,55,55,55,55,55,55,55,55,55,55,55,55,55,55,56,56,56,56,56,56,56,56,56,56,56,56,56,56,56,56,56,56,56,56,56,56,56,56,56,56,56,56,56,56,56,56,56,56,56,57,57,57,57,57,57,57,57,57,57,57,57,57,57,57,57,57,57,57,57,57,57,57,57,57,57,57,57,57,57,57,57,57,57,57

上面的问题是我想要解决的问题，对此有任何帮助将不胜感激。

Answer 1

是的，问题是您有多个具有相同年份和周年值的记录。

创建一个日历表，其中表中只有一年 - 一年中的一对，并使用它来加入您的日志数据。
或者在查询中使用select distinct。

    select distinct calendar.YEAR,
       calendar.WEEK_OF_YEAR,
       ifnull(count(data_transfer.id_data_transfer), 0) as DEVICE_TO_DEVICE,
       ifnull(count(device.tag_code), 0) as DEVICE_REGISTRATIO
     from...

或者从子日历表中的日历表中获取不同的年 - 星期对，并在设备和data_transfer表上加入此派生表。


select c.YEAR,
       c.WEEK_OF_YEAR,
       ifnull(count(data_transfer.id_data_transfer), 0) as DEVICE_TO_DEVICE,
       ifnull(count(device.tag_code), 0) as DEVICE_REGISTRATION
from (select distinct YEAR, WEEK_OF_YEAR FROM calendar) c
left join data_transfer 
    on data_transfer.WEEK_NUMBER=c.WEEK_OF_YEAR -- wee number
        and data_transfer.year = c.YEAR -- need the year of week
        and data_transfer.id_customer = 1 --  specific customer
        and data_transfer.cloud_type is null --  specific type etc
        and date(data_transfer.TRANSFER_START_TIME) > date(date_sub(now(), INTERVAL 1 YEAR)) -- for the final week to be this week
left join device 
    on device.WEEK_NUMBER = c.WEEK_OF_YEAR       
        and device.year = c.YEAR
        and device.ID_CUSTOMER = 1
        and date(device.DEVICE_CREATE_DATE) > date(date_sub(now(), INTERVAL 1 YEAR)) -- for the final week to be this week
where date(calendar.date) > date(date_sub(now(),INTERVAL 1 YEAR)) -- for the final week to be this week
group by c.year, c.WEEK_OF_YEAR
order by c.year, c.WEEK_OF_YEAR;

Mysql，select语句引用日期（weekofyear）

1 个答案: