Question

这是我的主要方法：

public static void main(String[] args) {

    BasicCookieStore cookieStore = null;
    HttpResponse httpResponse = null;
    HttpClient httpClient = HttpClients.createDefault();
    while (true) {
        HttpUriRequest request = new HttpGet("http://hc.apache.org/httpcomponents-client-ga/httpclient/apidocs/org/apache/http/impl/client/HttpClientBuilder.html");
        try {
            httpResponse = httpClient.execute(request);
            System.out.println(httpResponse.getStatusLine().getStatusCode());
        } catch (Exception e) {
            System.out.println(httpResponse.getStatusLine().getStatusCode());
            e.printStackTrace();
        }
    }
}

执行2次后，HttpClient停止执行相同的HttpGet。虽然，我在循环中实例化一个新的HttpClient，但它不会停止。如果有什么策略阻止HttpClient执行相同的HttpGet方法超过2次，我会徘徊？谁能帮助我，我将非常感激！

Answer 1

客户端正在使用连接池来访问Web服务器。见HttpClientBuilder#build()。创建默认的httpclient并且未指定任何内容时，它会创建一个大小为2的池。因此，在使用2之后，它会无限期地等待尝试从池中获取第三个连接。

您必须阅读响应或关闭连接才能重新使用客户端对象。

请参阅更新的代码示例：

public static void main(String[] args) {

    BasicCookieStore cookieStore = null;
    HttpResponse httpResponse = null;
    HttpClient httpClient = HttpClients.createDefault();
    while (true) {
        HttpUriRequest request = new HttpGet("http://hc.apache.org/httpcomponents-client-ga/httpclient/apidocs/org/apache/http/impl/client/HttpClientBuilder.html");
        try {
            httpResponse = httpClient.execute(request);
            httpResponse.getEntity().getContent().close();
            System.out.println(httpResponse.getStatusLine().getStatusCode());
        } catch (Exception e) {
            System.out.println(httpResponse.getStatusLine().getStatusCode());
            e.printStackTrace();
        }
    }
}

执行两次后，HttpClient在循环中停止执行相同的HttpGet方法

1 个答案: