Question

我使用以下内容突出显示日期大于当前日期的日期字段。

    db.stock_task.ESI_withhold_until_date.represent=lambda v,
    row:SPAN(datetime.date(v),_class='withhold' if v and v> 
    datetime.date.today()else None)

    db.stock_task.withhold_until_date.represent = lambda v, row:
    SPAN(prettydate(v),_class='withhold' if v and v>datetime.date.today()
    else None)

错误日志：

Traceback (most recent call last):
        File "/home/tony/web2py/gluon/restricted.py", line 227, in restricted
        exec ccode in environment
        File "/home/tony/web2py/applications/cps5c/controllers/default.py", 
        line 562, in <module>
        File "applications/cps5c/modules/plugin_sqleditable/editable.py", 
        line 415, in extract
        r=func()
        File "/home/tony/web2py/gluon/tools.py", line 3774, in f
        return action(*a, **b)
        File "/home/tony/web2py/applications/cps5c/controllers/default.py", l
        ine 268, in stock_tasks
        db.stock_task.created_by,
        File "/home/tony/web2py/gluon/sqlhtml.py", line 2717, in grid
        nvalue = field.represent(value, row)
         File "/home/tony/web2py/applications/cps5c/models/db1.py", 
         line 144, in <lambda>

        db.stock_task.ESI_withhold_until_date.represent = lambda v,
        row: SPAN(datetime.date (v),_class='withhold' if v > 
        datetime.date.today()else None)

TypeError: an integer is required

如果我使用以下内容它可以正常工作。

    db.stock_task.withhold_until_date.represent = lambda v, row:
    SPAN(prettydate(v),_class='withhold' if v and v>datetime.date.today()
    else None)

任何帮助表示赞赏

欢呼声

Answer 1

db.stock_task.ESI_withhold_until_date.represent = lambda v, row: SPAN(v,_class='withhold' if v > datetime.date.today()else None)

web2py，TypeError：需要一个整数

1 个答案: