在python中对齐列表中的元素

Question

我正在尝试从数据库中获取值。当我打印时;我得到以下序列

- ('Total Row(s):', 4)
- [202]
- [226]
- [561]
- [23]

但我需要他们转换为list = [202,226,561,23]等列表，但我无法得到这个。所有元素都显示在第0位。     有人可以帮帮我吗？

这是我的代码，我正在连接mysql，我正在连接mysql：

import mysql.connector
from mysql.connector import MySQLConnection, Error
conn = mysql.connector.connect(host='examplecom',
                               database='niya')                 
        cursor = conn.cursor()
        old_Value = raw_input("Please enter old Pincode: ")
        print "Pincode is entered by you is : %s" % old_Value
        query_Value = ("select `id`,`type_id`,"
                       "mappings`.`facility_id`,"
                       "mappings`.`service_area_id` from `service_areas`,"
                       "`mappings` where mappings`.`service_area_id`=`id` "
                       "and `type_id`='{0}'".format(old_Value))           
        cursor.execute(query_Value, )
        rows = cursor.fetchall()
        print('Total Row(s):', cursor.rowcount)
        for row in rows:
            list_Id = [];
            facility_Id = int(row[2])
            list_Id.append(facility_Id)
            print list_Id

Answer 1

改变这个：

for row in rows:
    list_Id = [];
    facility_Id = int(row[2])
    list_Id.append(facility_Id)
    print list_Id

成：

list_Id = []
for row in rows:
    facility_Id = int(row[2])
    list_Id.append(facility_Id)
print list_Id

您为每一行创建了一个新列表，但想要一个包含所有ID的列表，即所有行。