我正在使用Databricks spark-csv包(通过Scala API),并且在定义自定义架构时遇到问题。
使用
启动控制台后spark-shell --packages com.databricks:spark-csv_2.11:1.2.0
我导入了必要的类型
import org.apache.spark.sql.types.{StructType, StructField, StringType, IntegerType}
然后只是尝试定义此架构:
val customSchema = StructType(
StructField("user_id", IntegerType, true),
StructField("item_id", IntegerType, true),
StructField("artist_id", IntegerType, true),
StructField("scrobble_time", StringType, true))
但是我收到以下错误:
<console>:26: error: overloaded method value apply with alternatives:
(fields: Array[org.apache.spark.sql.types.StructField])org.apache.spark.sql.types.StructType <and>
(fields: java.util.List[org.apache.spark.sql.types.StructField])org.apache.spark.sql.types.StructType <and>
(fields: Seq[org.apache.spark.sql.types.StructField])org.apache.spark.sql.types.StructType
cannot be applied to (org.apache.spark.sql.types.StructField, org.apache.spark.sql.types.StructField, org.apache.spark.sql.types.StructField, org.apache.spark.sql.types.StructField)
val customSchema = StructType(
我对scala很新,因此无法解析这个问题,但我在这里做错了什么?我正在关注非常简单的例子here。
答案 0 :(得分:8)
您需要将StructField
&#39}作为Seq
传递。
类似以下任何作品:
val customSchema = StructType(Seq(StructField("user_id", IntegerType, true), StructField("item_id", IntegerType, true), StructField("artist_id", IntegerType, true), StructField("scrobble_time", StringType, true)))
val customSchema = (new StructType)
.add("user_id", IntegerType, true)
.add("item_id", IntegerType, true)
.add("artist_id", IntegerType, true)
.add("scrobble_time", StringType, true)
val customSchema = StructType(StructField("user_id", IntegerType, true) :: StructField("item_id", IntegerType, true) :: StructField("artist_id", IntegerType, true) :: StructField("scrobble_time", StringType, true) :: Nil)
我不确定为什么它在README上没有显示,但是如果你查看了http://docs.telerik.com/kendo-ui/api/javascript/ui/grid#events-columnResize文档,那么它就清楚了。