Question

我在Symfony2中构建一个博客，它有两个实体：Blog和BlogComment（这是一个简化的例子）。 Blog与BlogComment具有OneToMany关系。发布BlogComment后，属性published将设置为false。管理员批准BlogComment后，会将其设置为true。

我想在我的所有Blog个帖子中创建一个概述，并在两个单独的字段中显示BlogComment和published = true的{{1}}个数。可以将所有published = false放在一个循环中并计算，但因为它可能是BlogComment的非常大的概述 - 这不是我的首选选项。

我在Blog创建了两个属性：Blog和published_comments_count。为了更新这些字段，我创建了一个unpublished_comments_count的监听器：

BlogComment

它工作得很好，但是当我添加一个新注释时，它还不在class BlogCommentListener { public function onFlush(OnFlushEventArgs $args) { $em = $args->getEntityManager(); $uow = $em->getUnitOfWork(); $entities = array_merge( $uow->getScheduledEntityInsertions(), $uow->getScheduledEntityUpdates(), $uow->getScheduledEntityDeletions() ); foreach($entities as $entity){ if($entity instanceof BlogComment){ $Blog = $entity->getBlog(); $published_comments_count = 0; $unpublished_comments_count = 0; foreach($Blog->getComments() as $BlogComment){ if($BlogComment->getPublished()){ $published_comments_count++; } else { $unpublished_comments_count++; } } $Blog->setPublishedCommentsCount($published_comments_count); $Blog->setUnpublishedCommentsCount($unpublished_comments_count); $em->persist($Blog); $md = $em->getClassMetadata(get_class($Blog)); $uow->recomputeSingleEntityChangeSet($md, $Blog); } } } }的ArrayCollection中。有没有办法计算此ArrayCollection中的更改？

Answer 1

我认为不可能计算arrayCollection中的更改，但您可以通过为每个实体添加或删除1来更改逻辑：

class BlogCommentListener
{
    public function onFlush(OnFlushEventArgs $args)
    {
        $em = $args->getEntityManager();
        $uow = $em->getUnitOfWork();

        $insertions = $uow->getScheduledEntityInsertions();
        $deletions = $uow->getScheduledEntityDeletions();

        foreach($insertions as $entity){
            if($entity instanceof BlogComment){
                $Blog = $entity->getBlog();

                $Blog->setUnpublishedCommentsCount($Blog->getUnpublishedCommentsCount()+1);//Here the comment inserted must be unpublished

                $em->persist($Blog);

                $md = $em->getClassMetadata(get_class($Blog));
                $uow->recomputeSingleEntityChangeSet($md, $Blog);
            }
        }
    }
    foreach($deletions as $entity){
        if($entity instanceof BlogComment) {
            $Blog = $entity->getBlog();

            if ($entity->getPublished()) {

                $Blog->setPublishedCommentsCount($Blog->getPublishedCommentsCount()-1);//Here the comment inserted must be unpublished
            } else {
                 $Blog->setUnpublishedCommentsCount($Blog->getUnpublishedCommentsCount()-1);
            }                
            $em->persist($Blog);

            $md = $em->getClassMetadata(get_class($Blog));
            $uow->recomputeSingleEntityChangeSet($md, $Blog);
        }
    }
}

奖励方面，我会让您更容易解决问题：在树枝模板中使用计数过滤器：

{% for blog in blogs %}
    <li><h4>blog.title</h4>
    <p>comments published : {{ blog.comments.published|count }}</p>
    <p>comments non-published : {{ (not blog.comments.published)|count }}</p>
{% endfor %}

使用侦听器计算Symfony2中的缓存

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