我需要创建一个模型和方法,其中将填充相关模型的列表。
我的模型看起来像:
public class SearchHierarchyModel
{
public IList<Continent> Continent { get; set; }
public IList<Country> Country { get; set; }
public IList<City> City { get; set; }
}
我的方法应该做类似的事情:
public IList<SearchHierarchyModel> GetHierarchyFull(int Coninent_Id)
{
//pseduocode now
create lists of countries based on continent id
create lists of cities based on countries id from the prev. step
return a list of lists with relevant countries and cities
}
模型类
public class Contient
{
public int Id { get; set; }
public string Name { get; set; }
}
public class Country
{
public int Id { get; set; }
public string Name { get; set; }
public int ContientId { get; set; }
}
public class City
{
public int Id { get; set; }
public string Name { get; set; }
public int CityId { get; set; }
}
也许有更好的方法来实现这种层次结构?任何想法如何做到这一点?也许模型应该看起来不同?
答案 0 :(得分:2)
根据您的人际关系设置方式,可以做类似的事情。
public IList<SearchHierarchyModel> GetHierarchyFull(int Continent_Id)
{
var continent = db.Continents.FirstOrDefault(c => c.Id == Continent_Id);
//Get all countries with a specified ContinentId
var countryList = db.Countries.Where(c => c.ContinentId == Continent_Id);
//Get all cities that have a matching CountryId from any country in the first list.
var cityList = db.Cities.Where(c => countryList.Any(cl => cl.Id == c.CountryId)).ToList();
//We need to get the original countryList as a true list rather than a collection of entities.
//If we had called ToList above, it would error out.
//If we had called ToList in the ForEach loop, we also would have issues.
var countryList2 = countryList.ToList();
var searchList = new List<SearchHierarchyModel>
{
new SearchHierarchyModel()
{
Continent = new List<Continent> { continent },
Country = countryList2,
City = cityList
}
};
return searchList;
}
现在有一些关于上述内容的评论。在我看来,您只需要一个特定大陆的国家及其城市列表。如果是这样的话,实体框架会让你更容易。
我会将我的核心模型更改为:
public class Continent
{
public int Id { get; set; }
public string Name { get; set; }
public virtual ICollection<Country> Countries { get; set; }
}
public class Country
{
public int Id { get; set; }
public string Name { get; set; }
public int ContinentId { get; set; }
public virtual Continent Continent { get; set; }
public virtual ICollection<City> Cities { get; set; }
}
public class City
{
public int Id { get; set; }
public string Name { get; set; }
public int CountryId { get; set; }
public virtual Country Country { get; set; }
}
然后我将层次结构模型设置为:
public class SearchHierarchyModel
{
public Continent Continent { get; set; }
public Country Country { get; set; }
public City City { get; set; }
}
现在我们可以将搜索功能更改为:
public IList<SearchHierarchyModel> GetHierarchyFull(int Continent_Id)
{
var countries = db.Countries.Where(c => c.ContinentId == Continent_Id);
var cities = db.Cities.Where(c => countries.Any(co => co.Id == c.Id));
var searchList = new List<SearchHierarchyModel>();
foreach (var item in cities)
{
var newItem = new SearchHierarchyModel
{
Continent = item.Country.Continent,
Country = item.Country,
City = item
};
searchList.Add(newItem);
}
return searchList;
}
现在,我们不是迭代列表列表,而是迭代所有可能返回值的列表。此外,通过修改模型,可以明确定义模型之间的关系。这意味着我可以更容易地引用它们并与之互动。
这是一个搜索方法,使用Linq反向遍历对象,切断foreach循环并删除所有额外的列表。
public IList<SearchHierarchyModel> GetHierarchyFull(int Continent_Id)
{
var continent = db.Continents.FirstOrDefault(c => c.Id == Continent_Id);
if (continent == null)
return null;
var searchList = (from item in continent.Countries
from city in item.Cities
select new SearchHierarchyModel
{
Continent = continent,
Country = item,
City = city
}).ToList();
return searchList;
}