我正在使用HttpUrlConnection
并使用POST方法从Web服务器获取一些数据。有时,我得到回复,有时我得到EOFexception
这些是我已经尝试过的解决方案:
1) System.setProperty("http.keepAlive", "false");
2) if (Build.VERSION.SDK != null && Build.VERSION.SDK_INT > 13) {
connection.setRequestProperty("Connection", "close");
}
以下是AsyncTask
课程的代码;
代码:
@Override
protected JSONObject doInBackground(KeyValuePair... keyValuePairs) {
JSONObject jsonResponse = new JSONObject();
HttpURLConnection connection = null;
// check if is Internet is available before making a network call
if (isInternetAvailable()) {
try {
jsonResponse = new JSONObject();
URL url = new URL(urlStr);
connection = (HttpURLConnection) url.openConnection();
connection.setRequestMethod("POST");
connection.setRequestProperty("Connection", "Keep-Alive");
connection.setUseCaches(false);
connection.setDoOutput(true);
connection.setRequestProperty("Content-Type", "application/x-www-form-urlencoded");
connection.setRequestProperty("charset", "UTF-8");
if (Build.VERSION.SDK != null && Build.VERSION.SDK_INT > 13) {
connection.setRequestProperty("Connection", "close");
}
// setting post params
StringBuilder builder = new StringBuilder();
for (int i = 0; i < keyValuePairs.length; i++) {
builder.append(URLEncoder.encode(keyValuePairs[i].getKey(), "UTF-8") + "=" + URLEncoder.encode(keyValuePairs[i].getValue(), "UTF-8") + "&");
GeneralUtils.print("key : " + keyValuePairs[i].getKey() + ", value : " + keyValuePairs[i].getValue());
}
String postData = builder.toString();
postData = postData.substring(0, postData.length() - 1);
GeneralUtils.print("postData " + postData);
byte[] postDataByteArr = postData.getBytes();
connection.setFixedLengthStreamingMode(postDataByteArr.length);
connection.setConnectTimeout(20000);
DataOutputStream dataOutputStream = new DataOutputStream(connection.getOutputStream());
dataOutputStream.writeBytes(postData);
dataOutputStream.flush();
dataOutputStream.close();
GeneralUtils.print("respCode " + connection.getResponseCode());
// if connection was not successful
if (connection.getResponseCode() != 200) {
jsonResponse.put("status", "Failure");
jsonResponse.put("message", "Something went wrong. Please Try Again");
} else {
BufferedReader reader = new BufferedReader(new InputStreamReader(connection.getInputStream()));
String line = null;
StringBuilder sb = new StringBuilder();
while ((line = reader.readLine()) != null) {
sb.append(line);
}
reader.close();
String response = sb.toString();
GeneralUtils.print("NetworkCall Server response " + response);
jsonResponse = new JSONObject(response);
}
} catch (JSONException e) {
GeneralUtils.print("NetworkCall.JSONEx 162 " + e);
} catch (MalformedURLException e) {
GeneralUtils.print("NetworkCall.MalformedURLEx " + e);
} catch (IOException e) {
try {
jsonResponse.put("status", "No Internet Connection");
jsonResponse.put("message", "Please check your Internet connection and try again");
} catch (JSONException e1) {
GeneralUtils.print("NetworkCall.JSONEx " + e);
}
} finally {
connection.disconnect();
}
} else {
// if Internet is not available
try {
jsonResponse.put("status", "No Internet Connection");
jsonResponse.put("message", "Please check your Internet connection and try again");
} catch (JSONException e) {
e.printStackTrace();
}
}
return jsonResponse;
}
许多人提前感谢!
答案 0 :(得分:0)
截至目前,我正在遵循发布here 的解决方法,该解决方案基本上要求尝试连接N次以绕过EOF异常问题。 在我的情况下,当我捕获EOFException时,我再次调用doInBackground,具体取决于reconnectCount;
CODE :
catch (IOException e) {
try {
if (reConnectCount <= 10) {
reConnectCount++;
jsonResponse = doInBackground(keyValuePairs);
} else {
jsonResponse.put("status", "No Internet Connection");
jsonResponse.put("message", "Please check your Internet connection and try again");
}
} catch (JSONException e1) {
GeneralUtils.print("NetworkCall.JSONEx " + e);
}
}
jsonResponse
基本上以JSON格式保存服务器响应。因此,只要doInBackground
成功执行(即没有得到Caught并返回jsonResponse),我们就会覆盖调用doInBackground的jsonResponse对象。