Question

我在laravel 5.1中使用ajax来获取sotre数据我有像这样的控制器

   public function store(Request $request)
{

    $validator = Validator::make($request->input(), [
        'username' => 'required',
        'password' => 'required',
    ]);
    if ($validator->fails()) {
        return view('common.adminwizard.technicianajax')->withErrors($validator)->withInput();
    }
}

当我使用withInput（）方法时ajax响应

Internal Server Error

但是当我删除这个方法时，ajax工作正常而不是传递数据
ajax脚本

$(document).on("click", "#test-submit-btn", function() {
$.ajax({
    type:'POST',
    url:'/test',
    data:$("#test_form").serialize(),
    success: function(result){
    $('#test_ajax_div').html(result);
},
error: function (xhr, ajaxOptions, thrownError) {
    alert(xhr.status);
    alert(thrownError);
}
})

Answer 1

我用这段代码解决了

     public function store(Request $request)
{

    $validator = Validator::make($request->input(), [
        'username' => 'required',
        'password' => 'required',
    ]);
    if ($validator->fails()) {
        return view('common.adminwizard.technicianajax')->withErrors($validator)->with(['request'=>$request]);

    }
}

当我在laravel 5.1中使用ajax时，使用withInput（）方法的Problam

1 个答案: