Question

我有这个控制器，但我不知道为什么当我访问/accounts/manageaccount.do时出现错误

public class ManageAccountController {

    public static final Logger LOGGER = Logger.getLogger    (ManageAccountController.class);        

    /**
     * 
     * @param request the http servlet request.
     * @param model the spring model.
     * 
     */ 
    @RequestMapping(value = "/accounts/manageaccount.do", method = RequestMethod.GET)
    public String showForm( @ModelAttribute("dataAccountCommand") final DataAccountCommand dataAccountCommand,
                            HttpServletRequest request, 
                            BindingResult result, 
                            Model model, 
                            Locale locale) {                            
        return "SHOW_VIEW";
    }

异常：org.springframework.web.bind.annotation.support.HandlerMethodInvocationException：无法调用处理程序方法[public java.lang.String fr.telecom.controller.accounts.ManageAccountController.showForm（fr.telecom.domain.formBeans） .DataAccountCommand，javax.servlet.http.HttpServletRequest，org.springframework.validation.BindingResult，org.springframework.ui.Model，java.util.Locale中）];嵌套异常是java.lang.IllegalStateException：声明的Errors / BindingResult参数没有先前的模型属性。检查处理程序方法签名！

Answer 1

您需要将BindingResult参数直接放在使用@ModelAttribute注释的参数之后。所以将您的签名更改为：

@RequestMapping(value = "/accounts/manageaccount.do", method = RequestMethod.GET)
    public String showForm( 
       @ModelAttribute("dataAccountCommand") final DataAccountCommand dataAccountCommand,  
       BindingResult result,       // moved up!                         
       HttpServletRequest request, 
       Model model, 
       Locale locale) {

        return "SHOW_VIEW";
    }

应该这样做。

另请参阅：http://viralpatel.net/blogs/errorsbindingresult-argument-declared-without-preceding-model-attribute/

在Spring 3.2.8中声明的错误/ BindingResult参数没有先前的模型属性

1 个答案: