如何在php

Question

我有像

这样的数据库

column A        Column B

2015-11-25      session 1
2015-11-26      session 1
2015-11-27      session 1
2015-11-28      session 2

我希望显示

Next session 1 is on - 25 Nov 2015, 26 Nov 2015, 27 Nov 2015

我尝试了GROUP BY列B，但它只返回一个第一个值。即2015年11月25日。

<?php
$sql = mysql_query("select * from  table GROUP BY column B HAVING COUNT(*) > 1 order by column A ASC");
 while($data=mysql_fetch_array($sql)){
?>

Next <?=$data['column B']?> Is On <b><?=date("d F Y",strtotime($data['coulmn A']));?>
<?}?>

Answer 1

使用GROUP_CONCAT，concat或group by

Select 
concat('Next ',b,' is on - ',GROUP_CONCAT(DATE_FORMAT(a,'%d %b %Y')))  
From table group by b

或DATE_FORMAT用于更改日期格式

Answer 2

试一试：

 <?php
    $sql = mysql_query("select ColumnA, ColumnB from  table GROUP BY columnB, ColumnA HAVING COUNT(*) > 1 order by column A ASC");
     while($data=mysql_fetch_array($sql)){
    ?>

    Next <?=$data['columnB']?> Is On <b><?=date("d F Y",strtotime($data['coulmnA']));?>
    <?}?>

Answer 3

这可能不是一种简单的方法，而是工作..

$result1 = mysqli_query($con, "select columnB from  table GROUP BY columnB, columnB HAVING COUNT(*) > 1 ");
while($data1 = mysqli_fetch_assoc($result1)){
    $ses = $data1['columnB'];
    $result2 = mysqli_query($con, "select columnA, columnB from table where columnB='$ses'");
    while($data2 = mysqli_fetch_assoc($result2)){
      var_dump($data2);
    }
}